A)
<span>10, 15, 17, 19, 25 </span>
<span>Min: 10 </span>
<span>Median: 17 </span>
<span>Max: 25 </span>
<span>lower Quartile: (10+15)/2 = 12.5 </span>
<span>upper Quartile: (19+25)/2 = 22 </span>
<span>b) </span>
http://imageshack.us/photo/my-images/22/...
<span>c) </span>
<span>Mean: (10 + 15 + 17 + 19 + 25)/5 = 17.2 </span>
<span>[ ( 17.2 - 10 )^2 + ( 17.2 - 15 )^2 + ( 17.2 - 17 )^2 + ( 17.2 - 19 )^2 + ( 17.2 - 25 )^2 ] / 5 = 24.16 </span>
<span>√( 24.16 ) ≈ 4.92 </span>
<span>-------------- </span>
<span>4) </span>
<span>[ 4. . .-2 . . . -12 ------> 3R1 - 4R2 ----> R2 </span>
<span>3. . .-1 . . . -3 ] </span>
<span>[ 4. . .-2 . . . -12 ------> R1 - R2 ----> R1 </span>
<span>0. . .-2 . . . -24 ] </span>
<span>[ 4. . ..0 . . . .12 ------> R1/4 ----> R1 </span>
<span>0. . .-2 . . . -24 ] R2/-2 ----> R2 </span>
<span>[ 1. . ..0 . . . .3 </span>
<span>0. . .1 . . . 12 ] </span>
<span>x = 3 & y = 12
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer:
Step-by-step explanation:
Note : <u><em>the total number of students is 55</em></u>
___________________________
p(A) = 40/55
p(B) = 15/55
Therefore,
She would need about 6 bags because 7*3=21 6+3=18 so about 6 bags
