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3 years ago

How do you find the median of a data set when you have an even number of values?

Mathematics

2 answers:

natima [27]3 years ago

3 0

Answer:

If there is an even number of numbers, the median is the average of the two numbers in the middle.

Step-by-step explanation:

To find the median of any set of numbers, put them in order from smallest to greatest. If a number occurs more than once, list it more than once. The number in the middle is the median. If there is an even number of numbers, the median is the average of the two numbers in the middle. For your first example, we line them up: 3, 6, 6.

kykrilka [37]3 years ago

3 0

Answer:

Set them from least to greatest and remove one from each side until you find the middle number! If you're left with 2, add them both and divide by 2.

Step-by-step explanation:

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I-Ready find the measure of angle RST

garik1379 [7]

Answer:

Step-by-step explanation:

You need an image for problem to be solved, please repost it with a image, so it can be solved

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3 years ago

One measure of general health is your body mass index (BMI). Adults with a BMI between 18.5 and 24.9 are generally considered to

soldi70 [24.7K]

Answer: 0.1797

Step-by-step explanation:

Given : $\mu=24.5\ \ ; \sigma=1.2$

Let x be the random variable that represents BMI for adults in this country.

We assume that BMI for adults in this country is normally distributed.

Then, z-score for x=25.6 , $\because z=\dfrac{x-\mu}{\sigma}$

$\Rightarrow\ z=\dfrac{25.6-24.5}{1.2}\approx0.9167$

Using z-value table , we have

The probability that the person's BMI is more than 25.6 :

$P(x>25.6)=P(z>0.9167)=1-P(z\leq0.9167)\\\\=1- 0.8203413=0.1796587\approx0.1797$

Hence, the probability that the person's BMI is more than 25.6 = 0.1797

Hence, the probability that the person's BMI is more than 25.6 = 0.1796

Hence, the probability of the stick's weight being 2.23 oz or greater = 0.0174

5 0

4 years ago

Parallelogram ABCD is translated (x + 3, y − 2) and then rotated 90° about the origin in the clockwise direction. Complete the t

Darya [45]

Answer: A″ (−1, 2), B″ (1, 1), C″ (1, −1), D″ (−1, −2)

Step-by-step explanation:

there are basically 2 parts in the question.

first one is the translation(easier one)

after translation, the corresponding points will be:

A (− 5, 1) --> a(-5+3,1-2) = (-2,-1)

B (−4, 3) --> b(-4+3,3-2) = (-1,1)

C (−2, 3) --> c(-2+3,3-2) = (1,1)

D (−1, 1) --> d(-1+3,1-2) = (2,-1)

now the second part:

let (x,y) be a point and if it is rotated by " $\alpha$ "

then, the new coordinates (x',y') will be :

x'= $xcos\alpha +ysin\alpha$

y'= $-xsin\alpha +ycos\alpha$

here, $\alpha = 90 degrees$

so,

a(-2,-1) --> A" $(-2cos[90]-1sin[90], -[-2]sin[90]+[-1]cos[90]) =(0-1, 2+0)=(-1,2)$

(since, cos[90]=0, sin[90]=1)

b(-1,1) -->B"(-1cos[90]+1sin[90], -[-1]sin[90]+1cos[90])=(1,1)

c(1,1) --> C"(1cos[90]+1sin[90],-[1]sin[90]+1cos[90]) = (1,-1)

d(2,-1) --> D"(2cos[90]+[-1]sin[90],-2sin[90]+[-1]cos[90]) =(-1,-2)

these are the coordinates after both the transformations.

7 0

4 years ago

Read 2 more answers

When Jim surveyed 5 sixth-grade students at the community skating rink, he found that only 1 out of the 5 had completed the

kati45 [8]

Answer: yes its a good inference

Step-by-step explanation:

its a good inference because if you multiply 32 by 5 it makes 160 and sense its 1 of every 5 it should be one fifth you find one fifth by dividing the hole number by 5 and reverse it by multiplying it by 5.

7 0

4 years ago

Suppose that 3 balls are chosen without replacement from an urn consisting of 3 white and 7 red balls. Assume moreover that the

zimovet [89]

Answer:

P(X1=1, X2=1) = 1/15

P(X1=1, X2=0) = 7/30

P(X1=0, X2=1) = 7/30

P(X1=0, X2=0) = 7/15

Step-by-step explanation:

Let Xi = 1 if the i-th white ball is selected. In this question the 3 white balls are marked 1,2 and 3.

We need to know the possible combination between X1 and X2 i.e. for the white ball 1 and 2 being chosen in the event.

We also need to note that the event is dependent which that after a ball is being chosen, it will not be put back hence affecting the probability of picking the next ball.

Consider all the possible combination between X1 and X2

a) both being chosen P(X1=1, X2=1)

= (3/10) x (2/9) = 1/15

Note that the first probability is the probability before any ball is being picked. The chances for ball white to be pick is 3/10 (3 white ball from the total 10 balls).

After 1 white ball being selected, that ball is not again out back into the urn making white ball 2 and total ball 9. Hence probability of picking another white ball is 2/9

b) only X1 chosen P(X1=1, X2=0)

= (3/10) x (7/9) = 7/30

After the white ball was picked, the probability of white not being pick again is the same as red being picked. Since there is still 7red balls and a total of 9 balls, the probability is 7/9

c) only X2 chosen P(X1=0, X2=1)

= (7/10) x (3/9) = 7/30

The white is not being picked first, making the probability of picking red is 7/10. Then the probability of white being picked is 3/9

d) both not chosen

P(X1=0, X2=0)

= (7/10) x (6/9) = 7/15

In other word only red being chosen. So the first probability is 7 red out of 10 balls (7/10), and the next red ball being picked next is 6/9

7 0

3 years ago