Step 1
Let n represent car and m represent motorcycles.
n + m = 50 ...................1
car has four wheels and motorcycle has two wheels
4n + 2m = 164 .............................. 2
Step 2
Solve equation 1 and 2 simultaneously.
from (1), make n subject of relation and substitute in equation 2.
n = 50 - m
Step 3
Substitute n in equation 2
4(50 - m) + 2m = 164
200 - 4m + 2m = 164
collect like terms
200 - 164 = 4m - 2m
36 = 2m
m = 36/2
m = 18
next find n
n = 50 - m
n = 50 - 18
n = 32
There are 32 cars and 18 motorcycles.
Answer:
11 ;
Step-by-step explanation:
Given the data:
30 27 22 25 24 25 24 15 35 35 33 52 49 10 27 18 20 23 24 25 30 24 24 24 18 20 25 27 24 32 13 13 21 2 37 35 32 33 29 3 28 28 25 29 31
Number of classes = 5
Class width : Range / number of classes
Class width = (maximum - minimum) / 5
Class width = (52 - 2) / 5 = 50/5 = 10 + 1 = 11
For the frequency table showing class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies and histogram
Kindly check attached picture
Subtitute f(x) with 2x + 1, and subtitute g(x) = -x + 4
f(x) = g(x)
2x + 1 = -x + 4
Then solve the equation above to find the value of x
Move the coefficient-variable x to the left side, and move the constants to the right side. When they are moved, addition becomes substraction, substraction becomes addition
2x + 1 = -x + 4
2x + x = 4 - 1
Simplify the equation
2x + x = 4 - 1
3x = 3
Move 3 on the left side to the right side, it becomes denominator
3x = 3
x = 3/3
x = 1
The solution to the equation is
x = 1
140 is a composite number. Factor pairs: 140 = 1 x 140, 2 x 70, 4 x 35, 5 x 28, 7 x 20, 10 x 14. Factors of 140: 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140. Prime factorization: 140 = 2 x 2 x 5 x 7, which can also be written 140 = 2² x 5 x 7
Answer:
20%
Step-by-step explanation:
1/5 as a percent is 20%
The 1 in 1/5 is equal to 10.
The 5 in 1/5 is equal to 50.
Therefore you would multiply 50 x 2 to get 100.
Then, you would multiply 10 x 2 to get 20/100 or 20%
