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Lynna [10]
3 years ago
7

Segments AB, EF, and CD intersect at point C, and angle ACD is a right angle. Find the

Mathematics
1 answer:
Dominik [7]3 years ago
3 0
G=37

Angle ACD and angle DCB are a linear pair. Meaning they are supplementary.

ACD=90 degrees

180-90=90

90 degrees equals the angle of DCB.

90-53=37

So g=37
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Write an expression for the sequence of operations described below. triple v, then subtract 7 from the result Do not simplify an
oee [108]

Given:

The sequence is defined as "triple v, then subtract 7 from the result".

To find:

The expression for the given sequence.

Solution:

Triple v means 3 times of v, i.e., 3v.

So, the result is 3v.

Then subtract 7 from the result. So, the expression for the sequence is

3v-7

Therefore, the required expression is 3v-7.

6 0
3 years ago
A(x, 1), B(5,3) and C(4,-3) are the vertices of triangle ABC. If AB=AC, find the value of x​
Molodets [167]

\\ \rm\longmapsto AB=AC

\\ \rm\longmapsto \sqrt{(x-5)^2+(1-5)^2}=\sqrt{(x-4)^2+(1+3)^2}

\\ \rm\longmapsto (x-5)^2+(-2)^2=(x-4)^2+4^2

\\ \rm\longmapsto (x-5)^2+4=(x-4)^2+16

\\ \rm\longmapsto (x-5)^2-(x-4)^2=16-4=12

\\ \rm\longmapsto x^2-10x+25-x^2+8x-16=12

\\ \rm\longmapsto -2x+9=12

\\ \rm\longmapsto -2x=12-9=3

\\ \rm\longmapsto x=\dfrac{3}{-2}=-1.5

5 0
3 years ago
Read 2 more answers
Add or subtract (m^2-m+3)+(m-1)?
uysha [10]
First You would rewrite the equation:
M^2-m+3+m-1
Second: rewrite equation to Combine like terms
M^2-m+m+3-1
Answer:
M^2+2
4 0
3 years ago
Read 2 more answers
PLEASE HELP ME <br> I don’t know how to solve this one please give me a good explanation
forsale [732]
You have to use the distributive property, therefore you get 2x+13/3.

The next step is to do 2 x 5 because they gave us a number for the variable x. Then you have to do 2 x 13 which gives us 26.

10+26=36 and 36/3=12, hope I helped, Have a nice day! :)
3 0
2 years ago
Read 2 more answers
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10.
Firdavs [7]

Answer:

New can holds 112.25\,\,cm^3 more than the old can

Step-by-step explanation:

Given: Diameter of the can is 6 cm and height is 12 cm such that volume of can is 339.12\,\,cm^3

Dimensions of the can are increased by a multiple of 1.10

To find: Difference between the volume of new can and volume of old can

Solution:

Volume of can (v) = 339.12\,\,cm^3

Let r, h denote radius and height of the can.

Let R, H denotes radius and height of the new can.

r = diameter/2 = \frac{6}{2}=3\,\,cm

h = 12 cm

R = 3(1.1)=3.3.\,\,cm

H = 12(1.1)=13.2\,\,cm

New volume (V) = \pi (R)^2H=\pi(3.3)^2(13.2)=451.37\,\,cm^3

So,

V-v=451.37-339.12=112.25\,\,cm^3

7 0
4 years ago
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