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dangina [55]
3 years ago
14

Jen can bike 12 miles in 40 minutes. How much time will she need to bike 30 miles if her speed remains the same? PLEASE HELP QUI

CK
Mathematics
2 answers:
murzikaleks [220]3 years ago
5 0

Answer: 100 minutes

Step-by-step explanation:

With the given information, we can use a proportion to figure out how long it would take for Jen to bike 30 miles.

\frac{12mi}{40min} =\frac{30mi}{x} \\

12x=30*40

12x=1200

x=100

Phoenix [80]3 years ago
4 0
Answer:
100

40 divided by 12 and then multiply it by 30.
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Answer:

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Factor the Expression x^2+x+7
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At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the n
pickupchik [31]

Answer:

12 possible outcomes.

Sample space:

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

Step-by-step explanation:

The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.

1. There are four possible outcomes for the first wheel: F, A, I and R

2. There are three possible outcomes for the second wheel: 1, 2 and 3

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3 years ago
Help help help help please business
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Answer:

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Step-by-step explanation:

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Then, just solve for x:

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Read 2 more answers
Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

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Let's cancel out the fraction by multiplying both sides by -2. So:

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The right side cancels:

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Flip:

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Case II:

We have:

1=x

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x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
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