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faust18 [17]
3 years ago
5

Please help me out .

Mathematics
1 answer:
Ann [662]3 years ago
3 0

Answer:

Answer a) length = x - 2

Answer b) area = 6x - 12

Answer c) perimeter = 2x + 8

Step-by-step explanation:

Any rectangle has a width and a length.

Given is width = 6 cm

The length is at this moment unknown, but we know something important. The length of this rectangle is 2 less than the diagonal. Lets call the length of the diagonal as x.

So although we do not actually know how long the diagonal is, we can still "pretend" it's value to be x. That is perfectly allowed, isn't it?

That way, the length = x-2. ( because that info was also given). Just don't worry to leave x in your answer :-).

Answer a) length = x - 2

So length = x - 2 and width = 6

The rest is easy!

area = width * length

area = 6 * (x - 2)

Answer b) area = 6x - 12

perimeter = 2 * width + ( 2 * length )

perimeter = 2 * 6 + ( 2 * (x - 2) )

perimeter = 12 + ( 2x - 4 )

perimeter = 2x + 8

Answer c) perimeter = 2x + 8

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Triangle ABC is formed by the vertices A(1,2,-1), B(-3,-6,2)and C(3,-2,0).
Vesnalui [34]

Answer:

Point D: (0,-4, 1 )

<em>d</em> = √41

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Pre-Calculus</u>

  • Midpoint Formula [3D]: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )
  • Distance Formula [3D]: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point A(1, 2, -1)

Point B(-3, -6, 2)

Point C(3, -2, 0)

<u>Step 2: Find Point D</u>

Simply plug in your coordinates B and C into the midpoint formula to find midpoint

  1. Substitute [MF]:                    (\frac{-3+3}{2},\frac{-6-2}{2}, \frac{2+0}{2} )
  2. Add/Subtract:                       (\frac{0}{2},\frac{-8}{2}, \frac{2}{2} )
  3. Divide:                                  (0,-4, 1 )

<u>Step 3: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates A and D into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                    d = \sqrt{(0-1)^2+(-4-2)^2+(1+1)^2}
  2. Subtract/Add:                       d = \sqrt{(-1)^2+(-6)^2+(2)^2}
  3. Exponents:                           d = \sqrt{1+36+4}
  4. Add:                                      d = \sqrt{41}
5 0
3 years ago
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