F(x,y)=8x+y
This means, f is a function where we plug in pairs of numbers.
then, f calculates the first number times 8, to which it then adds the second number we plugged.
let's calculate f for the vertices:
f(0,0)=8*0+0=0+0=0
f(4, 0)=8*4+0=32+0=32
f(3, 5)=8*3+5=24+5=29
f(0, 5)=8*0+5=0+5=5
the maximum value of f is 32
the minimum value of f is 0
Answer: 71
Step-by-step explanation: A triangle adds up to 180 so you subtract 28 and 81 from 180 to get your answer
Answer:
It would be best to buy the two regular sized ones
Step-by-step explanation:
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
Answer:
A = 2
Step-by-step explanation:
When there are no solutions for x, both sides x cancel leaving an equation with two distinct numbers equal to each other (e.g. 6 = 0). Therefore, we must find a number A for which that happens.
Lets first simplify the equation, 3Ax - 24 = 5x - 9 + x = 6x - 9.
We want to cancel out the 6x on both sides. This happens when the left side also has 6x, so 3Ax = 6x -> A = 2.
Testing out this works, we get:
6x - 24 = 6x - 9 -> -24 = -9 (which isn’t true)
We get no solutions, which is what we are looking for! Therefore, A = 2 must be our answer!
I hope this helps! :)
