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Fynjy0 [20]
4 years ago
8

Prove that the sum of 3 consecutive numbers is always a multiple of 3

Mathematics
1 answer:
Bad White [126]4 years ago
7 0

Proof:

3 consecutive integers are x, x+1 , x+2.

Add these values.

x+x+1+x+2

3x+3

3×(x+1)

3(x+1) is the multiple of 3 for any integer value of x.

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Answer:

g(x)

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y-intersect of g(x) is 3 as shown in the drawing

as seen across the three y-intersects, the value of g(x) y-intesect is the greatest

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PLEASE HELP ASAPPPP!!!!!!!!
Lisa [10]

Answer:

slope: 1.25

Part B: The order in which the points are given does not change the value of the slope

Step-by-step explanation:

Part A. Given two points we can find slope using the slope formula

m = \frac{y_2-y_1}{x_2-x_1}

Given the points ( -6, 1/2) and ( -4,3 )

We plug in the y values and x values (starting with the last point give )

m=\frac{3-.5}{-4-(-6)} \\3-\frac{1}{2} =2.5\\-4-(-6)=2\\\frac{2.5}{2} =1.25\\

so we can conclude that the slope of a line that passes through the points ( -6, 1/2) and ( -4,3 ) is 1.25

Part B. The order in which the points are given does not change the value of the slope

Observe -

* flip the order in which the points are given *

given (-4,3) and (-6,1/2)

we use the same formula

*plug in the y and x values starting with the last point*

m=\frac{.5-3}{-6-(-4)} \\.5 - 3=-2.5\\-6-(-4)=-2\\\frac{-2.5}{-2} =1.25

The slope still equals 1.25 meaning that the order in which the points are given does not matter.

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