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I am Lyosha [343]
4 years ago
13

circle with a radius of 3 has a sector with a central angle of 17/9 pi radians. what is the area of the sector

Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
4 0

Answer:

17/2 pi

Step-by-step explanation:

Area of the whole circle is pi r², which is 9 pi

9 pi x 17/9 pi / 2 pi = 17/2 pi

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What is the equation of the following line written in slope-intercept form?
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Answer:

Option (2)

Step-by-step explanation:

Let the equation of the line is,

y - y' = m(x - x')

where (x', y') is a point lying on the given line.

And m = slope of the line = \frac{y_2-y_1}{x_2-x_1}

Line given in the graph passes through two points (-5, -1) and (-2, -3).

Slope of the line 'm' = \frac{-3+1}{-2+5}

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Therefore, equation of the line passing through(-5, -1) and slope of the line = -\frac{2}{3} will be,

y - (-1) = -\frac{2}{3}[x-(-5)]

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y=-\frac{2}{3}x-\frac{10}{3}-1

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Option (2) will be the answer.

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3 years ago
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3 years ago
What are the coordinates of a point in quadrant ||| which is 8 units away from point P please answer quick !!
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Step-by-step explanation:

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Let f(x) = x + 3 and g(x) = 1/x The graph of (gºf)(x) is shown below what is the range of ( gof) (x) .
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Answer:

The range of the function (g\°f)(x) is

B.  is all real numbers except y=0

Step-by-step explanation:

Given functions:

f(x)=x+3

g(x)=\frac{1}{x}

To find the range of (g\°f)(x).

Solution:

In order to find (g\°f)(x) , we will plugin f(x) in function g(x).

(g\°f)(x)=g(f(x))

(g\°f)(x)=\frac{1}{x+3}

The graph of the function (g\°f)(x) shows that

1) As x approaches -3 (but never touches the line x=-3), y tends to positive or negative infinity.

2) As y approaches 0 (but never touches the line y=0) , x tends to positive or negative infinity.

Thus, the range of the function is all real numbers except y=0

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