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alexdok [17]
3 years ago
11

Make r the subject of the formula

20%20%5Cfrac%7Bh%7D%7B3%7D%29" id="TexFormula1" title="v = \pi \: h {}^{2}(r - \frac{h}{3})" alt="v = \pi \: h {}^{2}(r - \frac{h}{3})" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

\boxed{r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  >   v= \pi {h}^{2}(r -  \frac{h}{3}  ) \\  \\  v=\pi {h}^{2}(r -  \frac{h}{3}  )is \:  equivalent  \: to   \:   {h}^{2}\pi(r -  \frac{h}{3}  ) = v: \\  =  >  {h}^{2}\pi(r -  \frac{h}{3}  ) = v \\  \\ Divide  \: both \:  sides  \: by  \: \pi  {h}^{2} :  \\  =  > r -  \frac{h}{3}  =  \frac{v}{\pi {h}^{2} }  \\  \\ Add \:   \frac{h}{3}  \:  to  \: both \:  sides:  \\  =  > r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} }

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Outcomes are equally likely of each is as likely to occur true or false
Brums [2.3K]

Answer:

true

Step-by-step explanation:

8 0
3 years ago
Find the volume of the ellipsoid x^2+y^2+9z^2=64
yuradex [85]
Parameterize the ellipsoid using the augmented spherical coordinates:

\begin{cases}x=\frac18\rho\cos\theta\sin\varphi\\\\y=\frac18\rho\sin\theta\sin\varphi\\\\z=\frac38\rho\cos\varphi\end{cases}

Then the Jacobian for the change of coordinates is

\mathbf J=\dfrac{\partial(x,y,z)}{\partial(\rho,\theta,\varphi)}=\begin{bmatrix}\frac18\cos\theta\sin\varphi&-\frac18\rho\sin\theta\sin\varphi&\frac18\rho\cos\theta\cos\varphi\\\\\frac18\sin\theta\sin\varphi&\frac18\rho\cos\theta\sin\varphi&\frac18\rho\sin\theta\cos\varphi\\\frac38\cos\varphi&0&-\frac38\rho\sin\varphi\end{bmatrix}

which has determinant

\det\mathbf J=-\dfrac3{512}\rho^2\sin\varphi

Then the volume of the ellipsoid is given by

\displaystyle\iiint_E\mathrm dx\,\mathrm dy\,\mathrm dz=\iiint_E|\det\mathbf J|\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

where E denotes the spaced contained by the ellipsoid. In particular, we have the definite integral and volume

\displaystyle\frac3{512}\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=1}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\dfrac\pi{128}
4 0
3 years ago
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Alex787 [66]

Answer:

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Larger number: 34

Step-by-step explanation:

Let x represent the smaller number.

Let 3x - 2 represent the larger number (The larger number is two less than three times the smaller number, or x)

x + 3x -2 = 46

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   Add 2 to both sides:

4x = 46 + 2

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4x = 48

    Divide both sides by 4:

4x/4 = 48/4

x = 12 is the smaller number

Since 12 is the smaller number, and the sum of the two numbers is 46, than the larger number must be 34.

I hope this helped you. If it did, please consider, rating, pressing thanks and/or giving my answer 'Brainliest.' Have a great day! :)

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3 years ago
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Answer:

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