Answer:
7x3=21
Step-by-step explanation:
pls mark Brainliest :)
Answer:
1041
Step-by-step explanation:
Among the numbers 1–1000, there are 31 squares, so the sequence will extend to at least 1031. In those added numbers, there is another square (1024), so the sequence must extend to at least 1032.
There are 7 more numbers that are cubes, but not squares, so the sequence must extend to at least 1039.
And there are 2 additional numbers that are 5th powers that are not squares or cubes. Compensating for the removal of these numbers extends the end of the sequence to 1041.
There are no numbers in this range that are both cubes and 5th powers and that have not already been accounted for. (The only 15th power is 1.)
Hence, the 1000th number in the sequence is 1041.
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This result is verified by a computer program that listed the numbers.
Worry man don’t understand maybe someone else can help
Just substitute (-3) wherever you see x
(-3)^2 -2(-3) +3= 9+6+3=18 ( SORRY IF IM WRONG OR DID IT WRONG?? )
Answer: x = the quantity of 5 plus or minus the square root of 29 all over 2
Step-by-step explanation:
The given quadratic equation is expressed as
x² - 5x - 1 = 0
The equation is already in the standard form of ax² + bx + c
The general formula for solving quadratic equations is expressed as
x = [- b ± √(b² - 4ac)]/2a
From the given quadratic equation,
a = 1
b = - 5
c = - 1
Therefore,
x = [- - 5 ± √(- 5² - 4 × 1 × - 1)]/2 × 1
x = [5 ± √(25- - 4)]/2
x = [5 ± √29]/ 2
x = ( 5 + √29)/- 2 or x = (5 - √29)/2
