Answer:
x<=2 is a
y<=x+1 is d
Step-by-step explanation:
Answer:
5 + sqrt(65), 5 - sqrt(65)
Step-by-step explanation:
x + y = 10
x×y = -40
so, two equations with 2 variables. using one equation to express one variable by the second. and then using the second equation to solve and calculate the second variable. and then by knowing the second variable we calculate the first.
=> x = 10 - y
=> (10-y)×y = -40
=> -1×(10-y)×y = 40
=> (y-10)×y = 40
=> y^2 - 10×y - 40 = 0
remember the solution for a quadratic equation
a×x^2 + b×x + c
is
x = (-b ± sqrt(b^2 - 4×a×c)/(2×a)
in our case
a = 1
b = -10
c = -40
and we used "y".
so,
y = (--10 ± sqrt((-10)^2 - 4×1×(-40))/(2×1) =
= (10 ± sqrt(100 + 160))/2 = (10 ± sqrt(260))/2 =
= (10 ± sqrt (4×65))/2 = 10/2 ± 2×sqrt(65)/2 =
= 5 ± sqrt(65)
=>
for y = 5 + sqrt(65), x = 10 - 5 - sqrt(65) = 5 - sqrt(65)
for y = 5 - sqrt(65), x = 10 - 5 + sqrt(65) = 5 + sqrt(65)
Answer:
D. Stephen
Hope This Helps! Have A Nice Day!!
Answer:
24
Step-by-step explanation:
It is done by Middle term splitting.
Taking the general equation ax² + bx + c, by middle term splitting, "b" should be splitted such that the numbers either on adding or on subtracting must be equal to "b" and their products must be equal to "a x c".
For example, in the question it's already given that the equation 8x² + bx + c is middle term splitted into 8x² + px + qx + 3.
So, that means "p x q" must be equal to "8 x 3", i.e., 24.
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Answer:
a. a(b)c
b. a(a(b)c)c
d. a(a(a(a)c)c)c
Step-by-step explanation:
We are given the following in the question:
a. a(b)c
It is given b belongs to W.
b. a(a(b)c)c
c. a(abc)c
a(abc)c does not belong to W because we cannot find x in W such that a(abc)c belongs to W.
d. a(a(a(a)c)c)c
e. a(aacc)c
a(aacc)c does not belong to W because we cannot find x in W such that a(aacc)c belongs to W.
