Question

Determine the intercepts of the line. 4x-1=3y+54x−1=3y+54, x, minus, 1, equals, 3, y, plus, 5 xxx-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis yyy-intercept: \Big((left parenthesis ,,comma \Big))

Answer 1

Answer:

The intercepts $(x,y) = (\frac{3}{2},-2)$

Step-by-step explanation:

Given:

$4x-1=3y+5$

Required

Determine the intercepts

The equation is a linear equation and the intercepts of the equation is calculated as thus;

For x intercepts; substitute 0 for y

$4x-1=3y+5$

$4x-1=3(0)+5$

$4x-1=0 + 5$

$4x-1=5$

Add 1 to both sides

$4x-1 + 1=5 + 1$

$4x = 6$

Divide both sides by 4

$\frac{4x}{4} = \frac{6}{4}$

$x = \frac{6}{4}$

Simplify fraction to lowest term

$x = \frac{3}{2}$

For y intercept, substitute 0 for x

$4x-1=3y+5$

$4(0)-1=3y+5$

$0 - 1 = 3y + 5$

$-1 = 3y + 5$

Subtract 5 from both sides

$-5 - 1 = 3y + 5 - 5$

$-6 = 3y$

Divide both sides by 3

$\frac{-6}{3} = \frac{3y}{3}$

$-2 = y$

Reorder

$y = -2$

Hence, the intercepts $(x,y) = (\frac{3}{2},-2)$

Answer 2

Answer:

0,-2

Step-by-step explanation: