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3 years ago

The height of a ball dropped from the top of a 450-foot tall building can be described by the expression

Mathematics

1 answer:

BaLLatris [955]3 years ago

8 0

Answer:

The answer is 386 feet.

Step-by-step explanation:

This equation simply asks to plug in a value that gives you the final value of the height. 450 is the initial height, and r (or l) is referred to as the amount of seconds after the item is dropped. 16 is the constant value of feet that the ball drops within one second.

Therefore, by substituting 4 for r (or l) and multiplying it by 16, you will receive 64 feet in 4 seconds. Finally, you need to subtract this from 450 feet, giving you a final answer of 386 feet.

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The houck family's train traveled 552 miles in 6 hours. The Roberts family traveled at 744 miles in 8 hours which family is trav

rusak2 [61]

Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.

Step-by-step explanation: Speed of Houck family's train = 552m/6hrs

speed of Robert family's train = 744m/8hrs.

Therefore considering Houck speed,

552miles = 6hours

1mile = (6 x 60)/552

= 360/552

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

For Robert

744miles = 8hours

1mile = ( 8 x 60 )/744

= (480/744)minutes

= 0.645

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

Conclusion: Both families were travelling at the same speed/rate.

To get that minutes in hour, just divide by 60 to get concert to hours.

6 0

4 years ago

Question 8

Nikolay [14]

The answer is C because 100 doesn’t change but 12 is dependent on the number of people.

5 0

3 years ago

Read 2 more answers

I really need help with this, my teacher doesn't really teach and I'm stumped again.

yarga [219]

Answer:

JMK = 54

JKH = 126

HLK = 90

HJL = 27

LHK = 63

JLK = 27

Step-by-step explanation:

Just use 180 for total angles in each triangle. Vertical angles mean the opposite to 126 is 126 and the other two that make up the inner vertices are (360- 126*2)/2 = 54

So, 126, `16, 54 , 54 are the inner angles in the circle. Just go from there.

5 0

3 years ago

What was the total amount of water in the tank before it was drained

OlgaM077 [116]

Answer:

c is the correct option

Step-by-step explanation:

please mark me as brainlist

4 0

3 years ago

Read 2 more answers

What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po

emmasim [6.3K]

$\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\left(\frac{\mathbf r_u\times\mathbf r_v}{\|\mathbf r_u\times\mathbf r_v\|}\right)\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dA$
$\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA$

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

$\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k$
$\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j$

The cross product is

$\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j$

So, the flux is given by

$\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA$
$\displaystyle\int_0^5\int_0^{2\pi}(-e^{-\sin v}\cos v+2\sin^2v)\,\mathrm dv\,\mathrm du$
$\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv$
$\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv$

where $t=-\sin v$ in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

$\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi$

5 0

3 years ago