No solution of the system of equations y = -2x + 5 and -5y = 10x + 20 ⇒ 2nd answer
Step-by-step explanation:
Let us revise the types of solutions of a system of linear equations
- One solution
- No solution when the coefficients of x and y in the two equations are equal and the numerical terms are different
- Infinitely many solutions when the coefficients of x , y and the numerical terms are equal in the two equations
∵ y = -2x + 5
- Add 2x to both sides
∴ 2x + y = 5 ⇒ (1)
∵ -5y = 10x + 20
- Subtract 10x from both sides
∴ -10x - 5y = 20
- Divide both sides by -5
∴ 2x + y = -4 ⇒ (2)
∵ The coefficient of x in equation (1) is 2
∵ The coefficient of x in equation (2) is 2
∴ The coefficients of x in the two equations are equal
∵ The coefficient of y in equation (1) is 1
∵ The coefficient of y in equation (2) is 1
∴ The coefficients of y in the two equations are equal
∵ The numerical term in equation (1) is 5
∵ The numerical term in equation (2) is -4
∴ The numerical terms are different
From the 2nd rule above
∴ No solution of the system of equations
No solution of the system of equations y = -2x + 5 and -5y = 10x + 20
Learn more:
You can learn more about the system of equations in brainly.com/question/6075514
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Answer:
11/15
Step-by-step explanation:
(1 × 5) + (2 × 3)
over
3 × 5
= 11/15
Answer:
The mean is 42, rounded to the nearest cant would be 42.00. IF this helped subscribe to Amiredagoat Yt
Step-by-step explanation:
What do you mean by "solve this?" Until you set f(x) = to some constant number, you don't have an equation and thus can't expect to find solutions.
Why don't we take <span>3x^2-18x+27 and set it = to 0, and only then try to solve this equation?
</span><span>3x^2-18x+27 = 0. Dividing both sides by 3, we get x^2 - 6x + 9= 0, which can be factored as
(x-3)^2 = 0. Taking the sqrt of both sides, we get x-3 = 0. Actually, there are 2 roots: 3 and 3. Again, this statement is true only if we set </span><span>3x^2-18x+27 = to 0.</span>
