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11Alexandr11 [23.1K]

2 years ago

10

Based on one of the Triangle Congruence Postulates, the two triangles are shown are congruent

1 answer:

tankabanditka [31]2 years ago

3 0

Answer:

true

Step-by-step explanation:

all the sides match up. One side (the base) is shared which means they are the same length. The triangle at the top has a single hash on a side and so does the bottom one. This means they are the same length. The same thing occurs with the last remaining sides, they are congruent because they both have two hash lines. Since all three sides of both triangle add up, the triangles ARE CONGRUENT.

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Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

$\sqrt{11-2x}=\sqrt{x^{2}+4x+4}$

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

$\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}$

$\sqrt{25}=\sqrt{25}$

$5=5$ ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

$\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}$

$\sqrt{9}=\sqrt{9}$

$3=3$ ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

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lord [1]

Answer: 115 is the answer

Step-by-step explanation:

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andrew11 [14]

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Step-by-step explanation:

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