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user100 [1]
3 years ago
15

2What is the diameter of this circle if the circumference is 30 inches?​

Mathematics
1 answer:
ioda3 years ago
8 0

Answer:

9.55 inches

Step-by-step explanation:

The diameter of a circle can be found by dividing the circumference by pi or 3.14. 30 divided by 3.14 is approximately 9.55.

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The triangle on the grid will be translated two units left. which shows the triangle translated 2 units left
Mariana [72]

Answer:

Take the coordinates of each vertex (corner point) and subtract 2 from the x-coordinate; leave the y-coordinate alone.

Step-by-step explanation:

Example: If one vertex is the point (5, 3), then it moves left 2 units to (3, 3).

If a vertex is at (-3, 1), then it moves 2 units left to (-5, 1).

5 0
3 years ago
I really need help with this!!!
netineya [11]
2 because is isisisisisisisisis
5 0
3 years ago
Find the perimeter of the triangle with vertices ​A(negative 2​,2​,3​), ​B(4​,negative 4​,3​), and ​C(7​,6​,4​).
gayaneshka [121]

Answer:

P\approx 28.872\,\text{units}

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

for the side AB: A(-2,2,3) and B(4,-4,3)

AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}

AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}

AB = \sqrt{72}

for the side BC: B(4,-4,3) and C(7,6,4)

BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}

BC = \sqrt{110}

for the side CA: C(7,6,4) and A(-2,2,3)

CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}

CA = \sqrt{98}

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

P = AB + BC + CA

P = \sqrt{72} + \sqrt{110} + \sqrt{98}

P\approx 28.872\,\text{units}

this is the perimeter of triangle ABC

6 0
3 years ago
What is the quotient in the polynomial form?
Oxana [17]

First step of a synthetic divison is that we need to carry down the leading coefficient. Here the leading coefficient is 2. So, carry down 2 at the bottom.

Next step is to multiply the divisor -3 with this carry down number 2. So, we have got 3*(-2)= -6 which will place atthe bottom of the next coefficient 4.

Next step is to add this column.

Now repeat the same method again till the last colum.

At the end we have got 0 after the addition. Which means the remainder is 0.

So, the quotient is 2x^2-2x+2.

8 0
3 years ago
Can someone help me with this? Plz.<br><br> Solve the quadratic equation 2x^2-4x-1=0
Mila [183]
You have to use the quadratic formula to solve this. The zeros of this quadratic are 2 + sqrt2/2 and 2 - sqrt2/2, which in "real" numbers is 1.707 and .2928
6 0
3 years ago
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