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Elis [28]
3 years ago
5

A high school Philanthropy Club is collecting plastic waste which will be used to create benches for a local park. The volume of

the
rectangular container, in cubu feel, used to hold the waste is modeled by the expression below, where x is the width of the container,
in feet
713 + 3,512
If the length of the container is half of a foot longer than its width, what expression represents the height of the container?
help please ​
Mathematics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

The expression 7x represents the height of the container.

Step-by-step explanation:

From the question:

We are being informed that; if the length of the container is half of a foot longer than its width.

Let the width be x;

Then the length of the container can now be ; x+1/2

We all known that the volume of a rectangular prism is : V= l×w×h

here;

l = length

w = width

h = height  

If we rewrite the given expression :

\mathbf{7x^3+3.5x^2};

Then we factor we make a similar coefficient  of  the above equation, the  remaining entities left in the parenthesis should be a linear term  with a leading coefficient of 1 to match the expression for the length of the container.

i.e

\mathbf{7x^3+3.5x^2}} \\ \\\mathbf{7x^2(x+1/2)}  \\ \\\mathbf{7*x*x*(x+1/2)}

Hence, if the length of the container is half a foot longer than its width, x, then the expression 7x represents the height of the container.

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What is the solution to this equation?
Fantom [35]

Answer:

x=-17

Step-by-step explanation:

<em>Original</em><em> </em><em>Equation</em><em>;</em>

<em>x</em><em>+</em><em>1</em><em>2</em><em>=</em><em>-</em><em>5</em>

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<em>x</em><em>=</em><em>-</em><em>5</em><em>-</em><em>1</em><em>2</em>

<em>There </em><em>are</em><em> </em><em>two negative </em><em>number</em><em> </em><em>so</em><em> </em><em>you </em><em>add</em><em> </em><em>them</em><em> </em><em>and</em><em> </em><em>when</em><em> </em><em>you </em><em>add</em><em> </em><em>them</em><em> </em><em>it</em><em> </em><em>would</em><em> </em><em>still</em><em> </em><em>be</em><em> </em><em>negative</em><em>.</em><em> </em><em>And</em><em> </em><em>you </em><em>would</em><em> </em><em>have </em><em>to</em><em> </em><em>add</em><em> </em><em>them </em><em>because </em><em>when</em><em> </em><em>there </em><em>are</em><em> </em><em>two</em><em> </em><em>negative</em><em> </em><em>numbers</em><em> </em><em>without </em><em>any</em><em> </em><em>other</em><em> </em><em>sign </em><em>you </em><em>will</em><em> </em><em>have </em><em>to </em><em>add</em><em> </em><em>so</em><em> </em><em>it's </em><em>going</em><em> </em><em>to </em><em>be</em><em>;</em>

<em>x</em><em>=</em><em>-</em><em>1</em><em>7</em>

<em>This </em><em>is </em><em>the </em><em>final</em><em> </em><em>answer</em><em>!</em><em>!</em><em>!</em>

7 0
2 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
Help i am in need of help fast pls
mr_godi [17]

Roxy: 42/9 = 4.67

Jordan: 79/18 = 4.39

Rickie: 123/27 = 4.56


Jordan has the lowest number of strokes per hole


Answer

Jordan

3 0
2 years ago
Read 2 more answers
Need some help with this please
saveliy_v [14]
-0.83 for it’s the lowest number
5 0
2 years ago
A fair coin is flipped two times. Which diagram shows all of the possible outcomes?
kirza4 [7]

Answer:

A

Step-by-step explanation:

It is the only one that has both heads and tails equally on all options, instead of heads heads or tails tails. There aren't any fair coins that are like that

hope this helps :)

6 0
2 years ago
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