With this diagram, what could be the values of c and d?

2. Determine the sum of the first 400 ODD numbers.

il63 [147K]

Odd numbers take the form $2n-1$ , where $n\ge1$ is an integer. When $n=400$ , the last odd number would be 799. So we're adding

$S=1+3+5+\cdots+795+797+799$

By reversing the order of terms, we have

$S=799+797+795+\cdots+5+3+1$

and we can pair up terms in both sums at the same position to write

$2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)$

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

$2S=400\cdot800\implies S=160,000$

###

We could also make use of the formulas,

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2$

We have

$S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000$

3 0

3 years ago

GET BRAINLIEST AND ALL MEH POINTS

11111nata11111 [884]

Answer: Look at the tenths place to round to the nearest whole number.

Compare the estimated sum to the actual sum.

The estimated answer is close to the actual answer.

Step-by-step explanation:

Sample respond :)

4 0

3 years ago

Read 2 more answers

A rectangular prism has a length of 1 yards, a width of 2) yards, and a height of 4 yards.

atroni [7]

Answer:

8

Step-by-step explanation:

2*1*4=8

5 0

3 years ago

a highway measures 58 and 1/2 miles long. There will be a speed limit sign posted every two one six miles. How many speed limit

Solnce55 [7]

a highway measures 58 and 1/2 miles long.there be a speed limit sign posted every two one six miles.How many speed limit signs Will be on the highway 

(C):29 .signs

4 0

2 years ago

Unknown to a medical researcher, 6 out of 25 patients have a heart problem that will result in death if they receive the test dr

Fiesta28 [93]

Using the hypergeometric distribution, it is found that there is a 0.0002 = 0.02% probability that exactly 6 patients will die.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

The values of the parameters for this problem are:

N = 25, k = 6, n = 8.

The probability that exactly 6 patients will die is P(X = 6), hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 6) = h(6,25,8,6) = \frac{C_{6,6}C_{19,2}}{C_{25,8}} = 0.0002$

0.0002 = 0.02% probability that exactly 6 patients will die.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

#SPJ1

8 0

1 year ago