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2 years ago

With this diagram, what could be the values of c and d?

Mathematics

1 answer:

Sedaia [141]2 years ago

7 0

Answer:

idk maybe

Step-by-step explanation:

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Solve the inequality: -6n - 12 >= 3(-n + 12)

Verizon [17]

Answer:

-16 > n or n < -16

Step-by-step explanation:

First, we can write the inequality and distribute.

-6n-12 > 3(-n+12)

-6n-12 > -3n+36

Get rid of a variable first (it makes solving a lot easier). We can add 6n to both sides.

-6n-12 > -3n+36

+6n +6n

-12 > 3n+36

Now, we can subtract 36 on both sides.

-12 > 3n+36

-36 -36

-48 > 3n

Divide by 3 on both sides.

-48 > 3n

/3 /3

-16 > n or (if it's easier) n < -16

Hope this helps!! Have a wonderful day C:

7 0

2 years ago

How long can late payments stay on your credit report?

ratelena [41]

The exception is if you are 60 days late often which will certainly hurt your scores. Otherwise, one late payment should not cause long term damage. 90 dayslate: This record will damage your credit scores significantly for up to seven years.

5 0

2 years ago

Introduction to complex numbers 5VV

sesenic [268]

Step-by-step explanation:

sqrt(-4) = sqrt(4×-1) = sqrt(4)×sqrt(-1) = 2i

6 0

1 year ago

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

4 0

3 years ago

Will give brainliest, Use properties of exponents to write an equivalent expression.

Sav [38]

Answer:

see attached

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers