3 years ago

$3,000 is invested in an account that earns 3% annually interest, compounded monthly.

Mathematics

1 answer:

umka2103 [35]3 years ago

6 0

Answer:

Initial P, principal value is $3000

Year 1: P(1)= 3000 + 3%(3000)

P(1)= 3090

Year 2: P(1)= 3090 + 3%(3090)

P(1)= 3182.70

etc.

So in year 10, using the formula for compound interest, P(t)= P(1.03)t

P(10)= 3000(1.03)10

= 4031.75

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