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Fudgin [204]
3 years ago
12

Please I need help on question #4!!

Mathematics
1 answer:
Otrada [13]3 years ago
5 0

Answer:

(a) 2,481,115 ways

(b) 1 way

(c) 2,572,999 ways

Step-by-step explanation:

<em><u>a</u></em> = we select 3 units from 250-3 = 247 nondefective units.

<em><u>b</u></em> = since there is a different order of the units that will lead to  the same units being selected, the order isnt actually important and therefore we really just need to use a combination. We have to select 3 unis from 3 defective units.

<em><u>c</u></em> = we select 3 units from 250 units

<u><em>Brainliest please, I need 4 more :P</em></u>

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Step-by-step explanation:

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By substituting eq(2) in eq(3), we get:

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Now substituting eq(2) & eq(4) in eq(1), we get

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Now putting the value of C in eq(2),

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A+49=134

A=134-49

A=85

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