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Elanso [62]
3 years ago
12

The purpose of this assignment is to determine a set of test cases knowing only the function’s specifications, reported hereaf

ter:The program takes as input a 2D matrix with N rows. The program finds the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. It records the indices of the columns, in order, in the array W. It records whether each value was positive or negative, in order, in the array T (+1 for positive, -1 for negative). Assume that all rows have at least one column with a non-zero value.As this is black-box testing, you will not have access to the source so you must use what you have learned.You need to include a comment that describes how you chose your test cases.Students should identify the input equivalence partitions classes and select test cases on or just to one side of the boundary of equivalence classes.Students will gain 25 points for each input equivalence partition classes and valid test cases reported.Any language can be used, preferably C or C++ but it's not an issue if it's not in these two. Thanks!
Computers and Technology
1 answer:
Nesterboy [21]3 years ago
5 0

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

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Norma-Jean [14]

Answer:

  • The graph of the function is attached below.
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  • The y-intercept will be: (-20, 0)

Explanation:

Given the function

f\left(x\right)\:=\:5x^2-\:20

As we know that the x-intercept(s) can be obtained by setting the value y=0

so

y=\:5x^2-\:20

switching sides

5x^2-20=0

Add 20 to both sides

5x^2-20+20=0+20

5x^2=20

Dividing both sides by 5

\frac{5x^2}{5}=\frac{20}{5}

x^2=4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

so the x-intercepts will be: (2, 0), (-2, 0)

we also know that the y-intercept(s) can obtained by setting the value x=0

so

y=\:5(0)^2-\:20

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y=-20

so the y-intercept will be: (-20, 0)

From the attached figure, all the intercepts are labeled.

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Answer:

Explanation:

The following vending machine program is written in Python. It creates various functions to checkItems, check cash, check stock, calculate refund etc. It calls all the necessary functions inside the main() function. The output can be seen in the attached picture below.

class Item:

   def __init__(self, name, price, stock):

       self.name = name

       self.price = price

       self.stock = stock

   def updateStock(self, stock):

       self.stock = stock

   def buyFromStock(self):

       if self.stock == 0:

           # raise not item exception

           pass

       self.stock -= 1

class VendingMachine:

   def __init__(self):

       self.amount = 0

       self.items = []

   def addItem(self, item):

       self.items.append(item)

   def showItems(self):

       print('Items in Vending Machine \n----------------')

       for item in self.items:

           if item.stock == 0:

               self.items.remove(item)

       for item in self.items:

           print(item.name, item.price)

       print('----------------\n')

   def addCash(self, money):

       self.amount = self.amount + money

   def buyItem(self, item):

       if self.amount < item.price:

           print('You can\'t but this item. Insert more coins.')

       else:

           self.amount -= item.price

           item.buyFromStock()

           print('You chose ' +item.name)

           print('Cash remaining: ' + str(self.amount))

   def containsItem(self, wanted):

       ret = False

       for item in self.items:

           if item.name == wanted:

               ret = True

               break

       return ret

   def getItem(self, wanted):

       ret = None

       for item in self.items:

           if item.name == wanted:

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               break

       return ret

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       price = item.price

       while self.amount < price:

               self.amount = self.amount + float(input('insert ' + str(price - self.amount) + ': '))

   def calcRefund(self):

       if self.amount > 0:

           print(self.amount + " refunded.")

           self.amount = 0

       print('Thank you!\n')

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   machine = VendingMachine()

   item1 = Item('Kit Kat',  1.5,  2)

   item2 = Item('Potato Chips', 1.75,  1)

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   item4 = Item('Gum',  0.50, 1)

   item5 = Item('Doritos',0.75,  3)

   machine.addItem(item1)

   machine.addItem(item2)

   machine.addItem(item3)

   machine.addItem(item4)

   machine.addItem(item5)

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   continueBuying = True

   while continueBuying == True:

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           machine.insertAmountForItem(item)

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           else:

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       else:

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           continue

if __name__ == "__main__":

   main()

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