Answer:
in this file you will find it https://xlbrands.com/wp-content/uploads/2014/06/DEW-POINT-CALCULATION-CHARTenglish.pdf
Explanation:
Answer:
= 49.674 g NaCl
Explanation:
From the equation;
1 mole of Sodium metal produces 2 moles sodium chloride
This means;
23 g of Na will produce 116.88 g of NaCl
Therefore;
11.5 g will generate;
= (11.5 × 116.88)/23
= 58.44 g of NaCl
But;
Percentage yield = (Actual yield/Theoretical yield)× 100%
85 /100 = Actual yield /58.44 g
Thus;
Actual yield = 0.85 × 58.44
= 49.674 g NaCl
The statement that best describes the effect of low ionization energies and low electronegativities on metallic bonding is the first one - the valence electrons are easily delocalized.
Due to these low energies and negativities, valence electrons can be moved around quite easily and their positions may be altered quite drastically.
Answer:
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From the reactions, 1.04 g of H2 and 7.995 g of aluminum phosphate is produced.
<h3>What is stoichiometry?</h3>
The term stoichiometry has to do with the amount of substances that participates in a reaction.
For reaction 1;
Mg + 2HCl → MgCl₂ + H₂
Number of moles of Mg reacted = 12.5 g/24g/mol = 0.52 moles
If 1 mole of Mg produced 1 mole of H2
0.52 moles produces 0.52 moles of H2
Mass of H2 = 0.52 moles * 2 g/mol = 1.04 g
For reaction 2;
2Li3PO4 + Al2(SO4)3 → 3Li2SO4 + 2AIPO4
Number of moles of lithium phosphate = 7.5 g/116 g/mol = 0.065 moles
2 moles of Li3PO4 produced 2 moles of AIPO4
0.065 moles of Li3PO4 produced 0.065 moles of AIPO4
Mass of AIPO4 = 0.065 moles * 123 g/mol = 7.995 g
Learn more about stoichiometry:brainly.com/question/9743981
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