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ki77a [65]
3 years ago
5

What will be the final temperature when a 25.0 g block of aluminum (initially at 25 °C) absorbs 10.0 kJ of heat? The specific he

at of Al is 0.900 J/g·C.
Chemistry
1 answer:
atroni [7]3 years ago
4 0
LET'S PUT IN WHAT WE KNOW!!!
Q
=
725 J
m
=
55.0 g
c
=
0.900 J/(°C⋅g)
Δ
T
=
final temperature - initial temperature
Δ
T
=
(
x
−
27.5
)
°C
We solve for
Δ
T
.
725 J
=
55.0 g
⋅
0.900 J/(°C⋅g)
(
x
−
27.5
)
°C
NOW IT'S JUST BASIC ALGREBRA
725
=
49.5
x
−
1361
2086
=
49.5
x
42.1
=
x
The final temperature is 42.1 °C.
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Answer:

Halo

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2 years ago
According to Avogadro's law, how will the number of molecules in 2 liters
dexar [7]

According to Avogadro's law, the two gases will have equal number of molecules.

<h3>Avogadro's law </h3>

From the question, we are to determine how the two gases would compare according to Avogadro's law

First, we will state the Avogadro's law

<em>Avogadro's law</em> states that "equal volume of all gases at the <u>same temperature and pressure</u> contain the same number of molecules"

Now, from the given information

We have 2 liters of hydrogen gas and 2 liters of oxygen gas at the <u>same temperature and pressure</u>

According to Avogadro's law, gases that are equal in volume and are at the same temperature and pressure will have equal number of molecules.

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5 0
2 years ago
determine the final temperature of a 10-0-g aluminum block originally at 25.0°C if you apply 435 joules of energy to it
mihalych1998 [28]
<span>Energy = Mass * heat capacity * temperature change so, 
</span>The energy added is 435 J and the temperature has to increase since the energy is added. 

<span>435 J = 10.0 g * 0.89 J/gC * temperature change </span>

<span>Temperature change = 48.9 C </span>

<span>The initial temperature is 25.0 C, the final temperature is 25.0 C + 48.9 C = 73.9 C.</span>
5 0
4 years ago
An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0
4 years ago
MOLES AND MOLAR MASS
shtirl [24]
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5 0
3 years ago
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