LET'S PUT IN WHAT WE KNOW!!! Q = 725 J m = 55.0 g c = 0.900 J/(°C⋅g) Δ T = final temperature - initial temperature Δ T = ( x − 27.5 ) °C We solve for Δ T . 725 J = 55.0 g ⋅ 0.900 J/(°C⋅g) ( x − 27.5 ) °C NOW IT'S JUST BASIC ALGREBRA 725 = 49.5 x − 1361 2086 = 49.5 x 42.1 = x The final temperature is 42.1 °C.