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Virty [35]
2 years ago
7

How many numbers between 1 and 100 (inclusive) are divisible by 4 or 5

Mathematics
1 answer:
BaLLatris [955]2 years ago
6 0

Answer: 40 numbers

Step-by-step explanation:

For us to do this, we will have to group the numbers in groups of 20.

You should note that from 1 to 20, there are 5 numbers that are divisible by 4 which are 4, 8, 12, 16, 20.

Also, there are 5 "20s" that are in 100, therefore 5 X 5 = 25 numbers that are divisible by 4.

Likewise, there are also 4 numbers that are divisible by 5 which are 5 , 10 , 15 , 20.

There are also 5 "20s" in 100, thos will give 5 x 4 = 20 numbers that are divsible by 5.

However, we have to subtract the numbers that are divisible by both 4 and 5 in order to prevent double counting.

These are 20, 40, 60, 80 and 100.

Thereforee, we will have:

25 + 20 - 5 = 40 numbers that are divisible by 4 or 5 from 1-100.

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Let T:V→W be a linear transformation from a vector space V into a vector space W. Prove that the range of T is a subspace of W.
9966 [12]

Answer:

The range of T is a subspace of W.

Step-by-step explanation:

we have T:V→W

This is a linear transformation from V to W

we are required to prove that the range of T is a subspace of W

0 is a vector in range , u and v are two vectors in range T

T = T(V) = {T(v)║v∈V}

{w∈W≡v∈V such that T(w) = V}

T(0) = T(0ⁿ)

0 is  Zero in V

0ⁿ  is zero vector in W

T(V) is not an empty subset of W

w₁, w₂   ∈ T(v)

(v₁, v₂ ∈V)

from here we have that

T(v₁) = w₁

T(v₂) = w₂

t(v₁) + t(v₂) = w₁+w₂

v₁,v₂∈V

v₁+v₂∈V

with a scalar ∝

T(∝v) = ∝T(v)

such that

T(∝v) ∈T(v)

so we have that T(v) is a subspace of W. The range of T is a subspace of W.

8 0
3 years ago
A jet travels 1464 mi against the wind in 2 hours and 1704 mi with the wind in the same amount of time. What is the rate of the
anastassius [24]
The jet rate against wind is 732 mi an hour (1464/2) and 852 with the wind (1704/2)
6 0
2 years ago
I would like some help. THanks.
ikadub [295]

Answer:

8.5

Step-by-step explanation:

Volume= base*height

V= 2 1/8*4

V= 8.5

7 0
3 years ago
A plane descended 922.02 meters in 5.5 minutes.<br> What is the plane's rate of descent?
UkoKoshka [18]
The rate of descent is <em>164.64 meters / minute
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<em />
<em />To get this answer you just divide the total number of meters descended by the total number of minutes passed. 
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So:<em>

</em>
922.02 ÷ 5.5 = 164.64

I hope this helped!! Have an amazing day! :D
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3 years ago
Which equation can you use to solve for figure shown?
DIA [1.3K]

Hey mate

Here is ur answer ...

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4 0
3 years ago
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