Answer:
20. im pretty sure it's sometimes, too
21. quickly
Explanation:
Ahhh i just did that assignment. it's she was a good person because her brother thought it would be better for her to be somewhere quiet and happy.. he felt she deserved it. because where they lived if she stayed she would die
Let me know if someone answers bc I have to do the same thing !!
★ Formula Applied :




★ Explanation :

Lets use substitution method ,
Let , u = sin2x
⇒ du = 2.cos2x.dx





★ Alternate Method :




]
