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Leni [432]
4 years ago
15

On a december day, the probability of snow is .30. the probability of a "cold" day is .50. the probability of snow and "cold" we

ather is .15. are snow and "cold" weather independent events?
Mathematics
1 answer:
Svetradugi [14.3K]4 years ago
7 0
Events A and B are independent if the following holds true:

P(A ∩ B) = P(A) * P(B)

where P(A ∩ B) is the probability of A and B, P(A) is the probability of A, and P(B) is the probability of B.

Setting A = "snow" and B = "cold weather", and plugging in the above numbers will give you the answer.
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Write the equation of a line in slope intercept form of a line that has a slope of 5 and a y
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Answer: y=5x-8

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3 years ago
Pemdas, thank you! <br>(-8 × -6) -4² ​
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32

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(-8 × -6) - 4² ​

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3 years ago
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A company did a quality check on all the packs of trail mixes it manufactured. Each pack of trail mixes is targeted to weigh 9.2
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If each pack of trail mixes is targeted to weigh 9.25 oz and must be within 0.23 oz of the target in order to be accepted, then rejected masses x, are those which weighs less than 9.02 oz or greater than 9.48 oz. 
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3 years ago
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The triangle below is equilateral. Find the length of side x to the nearest tenth.
Gemiola [76]

Answer:

\sqrt{\frac{15}{2} } or 2.738

Step-by-step explanation:

Let’s just look at the triangle on the top with the \sqrt{10} on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b=\frac{1}{2}(\sqrt{10}) or \frac{\sqrt{10} }{2}

Plugging these values into the equation:

x^2+ (\frac{\sqrt{10} }{2})^{2}=\sqrt{10} ^{2}

x^{2}=\sqrt{10} ^{2}-\frac{\sqrt{10} }{2} ^{2}

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x^{2} =\frac{15}{2}

x=\sqrt{\frac{15}{2} }

This approximately equals 2.738

5 0
2 years ago
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