Answer:
The Z score for this test is 1.3416
Step-by-step explanation:
According to the data given:
Null Hypothesis is: H0: p = 0.5
Alternative Hypothesis is: Ha: p > 0.5
Here the firm found 265 out of 500 heard pf the phone
p-cap = 265/500 = 0.53
n (sample size) = 500
Therefore, z = (p-cap – p)/√{p*(1-p)/n}
= (0.53 – 0.5)/√(0.5*0.5/500)
= 0.03/√(0.0005)
= 0.03/0.02236
= 1.3416
The Z score for this test is 1.3416