Answer: The required width of the park is 3 miles.
Step-by-step explanation: Given that a 5 mile jogging path diagonal divides a rectangular park in half and the park is 4 miles long.
We are to find the width of the park.
As shown in the attached figure below, the diagonal BD divides the rectangle ABCD into two equal parts,
where length DA = 5 miles, BD = 4 miles and AB = width = ?
Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.
Using Pythagoras theorem in triangle ABD, we have
Thus, the required width of the park is 3 miles.
Yes thats correct because they all equal eachother Ur right
138 x ? = 75
? = 75/138 = 0.544(3sf)
so about 54.35% (2dp) decrease
You can try finding numbers that are close to what you think you can use for exaple lets say we want to find the answer to 54x34 you could multiply 50x30 to get an estimated answer
The answer is (3, -7). If the function is written in the form y = a(x –
h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 – 48x
+ 65 in the form of a(x – h)^2 + k. g(x) = 8x^2 – 48x + 65. g(x) = 8x^2
– 48x + 72 - 72 + 65. g(x) = (8x^2 – 48x + 72) - 7. g(x) = (8 * x^2 – 8
* 6x + 8 * 9) - 7. g(x) = 8(x^2 - 6x + 9) - 7. g(x) = 8(x - 3)^2 - 7.
The function is now in the form a(x – h)^2 + k, where a = 8, h = 3, and k
= -7. Thus, the vertex is (3, -7).
