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8_murik_8 [283]
3 years ago
11

Simplify Negative 8 over 2 divided by 6 over negative 3.A. −4B. 2C. −2D. 4

Mathematics
2 answers:
svet-max [94.6K]3 years ago
7 0

Answer:

2

Step-by-step explanation:

-8/2 ÷ 6 / -3

Copy dot flip

-8/2 * -3/6

Simplify the fractions

-4 * -1/2

-4 / -2

2

Otrada [13]3 years ago
3 0

Answer:

(2)

Answer B is correct

Step-by-step explanation:

\frac{ - 8}{2}  \div  \frac{6}{ - 3}  \\  \frac{ - 8}{2}  \times  \frac{ - 3}{6}  \\  =  \frac{ 24}{12}  \\  =  (2)

hope this helps

brainliest appreciated

good luck! have a nice day!

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What fractions are equivalent to 1.27 repeating
Alina [70]
If the decimal is 1.2727272727272727 and repeating like that, then the fraction is 14/11

If the fraction is 1.27777777777777 and repeating like that, then the fraction is 23/18
8 0
3 years ago
Do line segments with the given lengths form a right triangle? State whether the line segments with the given lengths form a rig
Dvinal [7]

Given:

19, 180, 181

To be able to determine if the given lengths form a right triangle, the following condition must be met:

\text{ a}^2\text{ + }b^2=c^2

Let's check.

a.) At a = 19, b = 180, c = 181

\begin{gathered} \text{ a}^2\text{ + }b^2=c^2 \\ (19)^2+(180)^2=(181)^2 \\ 361\text{ + 32,400 = 32,761} \\ 32,761\text{ = 32,761} \end{gathered}

Therefore, the given lengths could form a right triangle at a = 19, b = 180 and c = 181.

The answer is yes.

It just happened to be that we got the right answer on the first try, you must also examine at a = 180, b = 181, c = 19 and a = 181, b = 19, c = 180 if the first try didn't meet the right condition.

If you failed to get, then the given lengths could not form a right triangle. The answer would be no.

4 0
1 year ago
Solve the system by substitution. SHOW WORK<br> -X - Y - Z=-8<br> - 4X +4Y +5Z=7<br> 2X + 2Z=4
jeyben [28]
Solve:

<span>-X - Y - Z       =-8
- 4X +4Y +5Z=7
2X + 2Z         =4   is the same as x + z = 2.  Thus, z = 2 - x.

Subst. 2 - x for z in the 1st and second equations.

</span>-X - Y - Z       =-8   becomes -x - y - (2 -x) = -8
- 4X +4Y +5Z=7     becomes -4x + 4y + 5(2-x) = 7

Now we have 2 equations in only 2 unknowns.  Let's simplify them!

-x - y - 2 + x = -8               which becomes   -y = -6, or y = 6
-4x + 4y + 10 - 5x = 7       which becomes   -9x + 4y = 7 - 10 = -3

Now substitute 6 for y in this last equation:  -9x + 4(6) = -3, or
                                                                      -9x + 24 = -3, or
                                                                      -9x = - 27 => x = 3

Then x = 3, y = 6 and z = 2 - x, or z = 2-3, or   z = -1.

The solution is (3, 6, -1).  Check it!!

3 0
3 years ago
HELP ILL GIVE BRAINLIEST
Scrat [10]
Part 1:
The process that arrow C signifies is the burning of fossil fuels in order to present carbon dioxide into the atmosphere. The mentioned procedure in the carbon cycle is comparatively new as humans were not able to generate huge concentrations of carbon dioxide by burning fossil fuels until the emergence of the Industrial revolution.
Part 2:
The phenomenon, which could discharge the compound into the air is the burning of fuels. It is an oxidation reaction in which the carbon present in the hydrocarbons in the fuel is oxidized to carbon dioxide by the presence of oxygen in the air. The carbon dioxide discharged into the atmosphere contributes to the greenhouse effect.
Part 3:
The elements, which produce it are conserved at the time of the carbon cycle by the Law of Conservation of Matter. According to this law, the matter is neither consumed nor produced, it only gets transformed. So, at the time of chemical procedures in the carbon cycle, the atoms of carbon are never destructed, however, they get rearrange and modify into distinct molecules. The mentioned cycle is essential for maintaining life on Earth.
5 0
3 years ago
Read 2 more answers
4(3x^2y^4)^3 / (2x^3y^5)^4
tatyana61 [14]

Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

8 0
3 years ago
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