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vredina [299]
3 years ago
7

Find the average rate of change over the given interval f(x)=3^x,[1,4]

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0

Answer:

26

Step-by-step explanation:

Thus, f(b)−f(a)b−a=3(4)−(3(1))4−(1)=26.

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Tpy6a [65]

Answer: ok i did :)

Step-by-step explanation: how are you?

6 0
3 years ago
What value of B will make the product equal of 17 in the following expression: 17xb/7
Katyanochek1 [597]

The value B is 7. If we apply B=7 the answer is 17 for the expression 17×\frac{b}{7}

Step-by-step explanation:

            The given expression is 17×\frac{b}{7}  

Step:1

            Form an equation from given data,

            17×\frac{b}{7}= 17..............................(1)

                                                         (∵ product equal to 17)

Step:2

            Check for alternatives by apply the value of B in eqn (1)

            Assume be value of B for check the equation

            B=1

            Equation becomes,

            17×\frac{1}{7} = 2.4286 ≠ 17

            Take, B=2,

            17×\frac{2}{7} = 4.8571 ≠ 17

            Take, B=3,

            17×\frac{3}{7} = 7.2857 ≠ 17

similarly,

            B=7,

            17×\frac{7}{7} = 17                       (∵ The product equals to 17)

Result:

         So, the answer for B is 7.

7 0
3 years ago
Read 2 more answers
Sas, sss, aas, or not enough information
lesya [120]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The given triangles are congruent by :

  • ASA criterion

because they have Two Angles and a side between them equal to the corresponding Angles and side of the another triangle.

3 0
2 years ago
WILL GIVE BRAINLIEST IF IT IS CORRECT.
Luba_88 [7]
I don’t know the answer too hope you find some that can help
6 0
2 years ago
A, B and C are events such that P(A) = 1/3, P(B) = ¼, and P(C) = 1/5. Find P(AUBUC) under each of the following assumptions: a)
marta [7]

(a) If A,B,C are mutually exclusive, then

P(A\cap B)=P(A\cap C)=P(B\cap C)=P(A\cap B\cap C)=0

so we have

P(A\cup B\cup C)=P(A)+P(B)+P(C)=\dfrac{47}{60}

(b) If A,B,C are mutually independent, then

P(A\cap B)=P(A)P(B),

P(A\cap C)=P(A)P(C),

P(B\cap C)=P(B)P(C),

P(A\cap B\cap C)=P(A)P(B)P(C)

so that

P(A\cup B\cup C)=P(A)+P(B)+P(C)-(P(A\cap B)+P(A\cap B)+P(B\cap C))+P(A\cap B\cap C)

P(A\cup B\cup C)=\dfrac{47}{60}-\left(\dfrac1{12}+\dfrac1{15}+\dfrac1{20}\right)+\dfrac1{60}

P(A\cup B\cup C)=\dfrac35

5 0
3 years ago
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