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ANEK [815]
3 years ago
12

Adam works for an agency

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0
Well that isn’t really a question but good for him
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Brunhilda has 6 children. She plans to give the same amount of pocket money (x dollars) to each of her children. She puts all th
Afina-wow [57]

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She kills all 6 and takes the money and keeps it for her self.

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3 years ago
How many fluid ounces of water is needed if a recipe requires 2 cups of water
Nana76 [90]

Answer:

16 i think

Step-by-step explanation:

8 0
3 years ago
A cylinder has a helght of 16 cm and a radius of 5 cm. A cone has a helght of 12 cm and a radius of 4 cm. If the cone is placed
erma4kov [3.2K]

Answer:

1055.04 cm³

Step-by-step explanation:

Given that,

Height of a cylinder, h = 16 cm

Radius of the cylinder, r = 5 cm

The height of a cone, h' = 12 cm

The radius of a cone, r' = 4 cm

The volume of the cylinder will be :

V=\pi r^2 h\\\\=3.14\times 5^2\times 16\\\\=1256\ cm^3

The volume of a cone is given by :

V'=\dfrac{1}{3}\pi r^2 h\\\\=\dfrac{1}{3}\times 3.14\times (4)^2\times 12\\\\=200.96\ cm^3

Volume of the air surrounding the cone Inside the cylinder = 1256 - 200.96 = 1055.04 cm³

Hence, the required answer is equal to 1055.04 cm³.

3 0
3 years ago
(a) Complete the table of values for y = 6 - 4x.<br><br> Please help ❤️
shutvik [7]

<u>Answer:</u>

\boxed{\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}

<u>Step-by-step explanation:</u>

Given equation to us is :-

\implies y = 6 - 4x

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u>

\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)}

<u>Hence </u><u>the</u><u> </u><u>final</u><u> </u><u>table</u><u> </u><u>would</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}

4 0
3 years ago
Solve the math problem
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