All categories

3 years ago

Renu wants to put a border of lace around a rectangular table cover 4 m long and 2 m wide..

Mathematics

1 answer:

GalinKa [24]3 years ago

8 0

Answer:12m

Step-by-step explanation:

The length of the lace required will be the same as that obtained by calculating the perimeter of that table, so p= (L+W)×2

Hence, P=(4m+2m)×2

P= 12m

You might be interested in

Drake needs to drill holes in a wooden plank. The holes will have a diameter of 0.5 millimeters, with an error allowance of 0.05

Tanzania [10]

Answer:

|x − 0.5| = 0.05

Step-by-step explanation:

Here x represents the diameter,

Since, an error of 0.05 millimeters is allowance in diameter,

Thus, the maximum acceptable diameter = x + 0.05,

And, the minimum acceptable diameter = x - 0.05

According to the question,

The holes will have a diameter of 0.5 millimeters,

Thus, x - 0.05 < 0.5 and 0.5 < x + 0.05

⇒ x - 0.5 < 0.05 and x - 0.5 > - 0.05

⇒ x - 0.5 < 0.05 and -(x -0.5) < 0.05

⇒ |x-0.5| < 0.05

⇒ Option D is correct.

6 0

2 years ago

Logan is making bookmarks that contain flower petals. He has 95 petals. He uses 3 flower petals for each bookmark. What is the G

Tcecarenko [31]

Answer: The GREATEST number of bookmarks that Logan can make = 31.

Step-by-step explanation:

GIven: Total petals = 95

Number of petals required for each bookmark = 3

Number the number of bookmarks can be prepared from 95 petals = 95 ÷ (Petals required of each bookmark)

= 95÷3

$=31\dfrac{2}{3}\ \ \ \approx31\text{ [Round to the nearest whole number.]}$

i.e. The GREATEST number of bookmarks that Logan can make = 31.

5 0

3 years ago

The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i

Anit [1.1K]

Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

$a_n = ar^{n-1}$

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

the first term can be calculated as:

$16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128$

Thus, the required geometric sequence is

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

4 0

3 years ago

In ∆ABC, AC = 15 centimeters, m B = 68°, and m C = 24°. What is BC to two decimal places?

Ahat [919]

16.17

(

)

Explanation:

In triangle ABC, side

, Angles are

∠

;

∠

and

∠

180

−

(

)

We know by sine law

sin

⋅

sin

16.17

(

)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which of these is an example of software?

MaRussiya [10]

A) windows, I learned this in a tech class I took

6 0

3 years ago