Answer:
B and E
Step-by-step explanation:
i took the test
First we need to find the slope of the original equation
2x - 3y = 3
-3y = -2x + 3
y = 2/3x - 1....the slope here is 2/3.
However, we need a perpendicular line...so we need to use the negative reciprocal slope. All that means is flip the slope and change the sign.
slope 2/3.....flip.....3/2....change the sign...-3/2.
so our perpendicular line will need a slope of -3/2.
y = mx + b
slope(m) = -3/2
(-8,2)...x = -8 and y = 2
now we sub and solve for b, the y int
2 = -3/2(-8) + b
2 = 12 + b
2 - 12 = b
-10 = b
so our perpendicular line is : y = -3/2x - 10
The x intercept is (5,0)
The y intercept is (0,2)
Answer:
No, because it does not have a constant rate of change.
Step-by-step explanation:
On the <em>x</em><em> </em>side of the table, there is a constant rate of change (+1). However, on the y side, it is not. The first change is +7, the next +5, and the last +6. The rate of change has to be constant on both sides for the table to be considered linear.
(x,y) or
(x,f(x))
so just plug the first value in and see if yo get the 2nd value
A. when x=-2, then is f(x)=48?
remember, x^-m=1/(x^m)
3(1/4)^-2=3/((1/4)^2)=3/(1/16)=3*16=48
true
B. x^0=1
so 3(1/4)^0=3(1)=3
true
C. when x=2
3(1/4)^2, 3(1/16), 3/16
true
D. 12
das is obviously false but anyway
3(1/4)^12=3(1/big number)=3/big number=small number but not zero
answer is A,B,C
