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Scorpion4ik [409]
3 years ago
15

Which equation represents the line that passes through (-6, 7) and (-3, 6)?

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

y=-3x+5

Step-by-step explanation:

<u>y²-y¹</u><u>=</u><u>gradient</u>

x²-x¹

<u> </u><u>6</u><u>-</u><u>7</u><u>=</u><u>gradient</u>

-3+6

-1/3=gradient

y-6/x+3=-1/3

y-6=-1/3(x+3)

y-6=-1/3x-1

y=-1/3x+5

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How to solve x in the equation 9x over 2 - 6=5
drek231 [11]

Step-by-step explanation:

\frac{9x}{2}  - 6 = 5 \\  \\  \therefore \:  \frac{9x}{2}  = 5 + 6 \\  \\  \therefore \:  \frac{9x}{2}  = 11 \\  \\  \therefore \: 9x = 11 \times 2 \\  \\ \therefore \: 9x = 22 \\  \\  \therefore \: x =  \frac{22}{9}  \\  \\  \therefore \: x =  2 \frac{4}{9}

3 0
3 years ago
Given that the points (-3, 2) and (1, 2) are vertices of a rectangle, what two sets of coordinates could form the other two vert
Lesechka [4]

Answer:

b

Step-by-step-by-step

explanation:

4 0
3 years ago
A recent study found that the average length of caterpillars was 2.8 centimeters with a
pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 2.8, \sigma = 0.7.

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 2.8}{0.7}

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0
2 years ago
PLZ HELP THIS IS HARD I WILL FIVE BRAINLIEST
bagirrra123 [75]

Answer:

2\frac{1}{3}\: ft

Step-By-Step Explanation:

Height\: of \:sail = 1\frac{1}{6}\:  ft = \frac{7}{6}\:  ft\\Base\: of \:sail = 4\:  ft \\Area\: of \:sail =\frac{1}{2} \times base \times height\\=\frac{1}{2} \times \frac{7}{6} \times 4\\= \frac{7}{6} \times 2\\=\frac{7}{3}\\=2\frac{1}{3}\: ft

6 0
3 years ago
5 (x+9) = 3 (x +8) + 2x
zmey [24]

Answer:

No solution

Step-by-step explanation:

Distribute

5x+45 = 3x+24+ 2x

Combine terms

45=5x-5x

45=0

This statement is not true so it is no solution

8 0
3 years ago
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