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Alex
4 years ago
15

What is the slope intercept form for a line that is parallel to y= 3x +2 and passes through (2,-4)

Mathematics
1 answer:
uysha [10]4 years ago
5 0

Answer:

same

Step-by-step explanation:

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I will mark as brainiest
Margaret [11]

If two triangles are similar, then their side lengths are proportional.

RS / JK = RT / JL

5 / x = 4 / 7

4x = 35

x = 35/4 = 8.75

RT / JL = TS / LK

4 / 7 = 6 / (y + 2)

42 = 4(y + 2)

42 = 4y + 4

4y = 38

y = 38/4 = 9.5

LK = 9.5 + 2 = 11.5 cm

JK = x = 8.75

Hope this helps!

8 0
2 years ago
Draw and lable a pentagon and a quadrilateral
Drupady [299]
Ok sweetie so the pentagon is the shape of a house like the first picture and quadrilateral  shapes are these on the second file attached to this answer

hope i helped in any shape or form so... have a great day and goodluck on you thing

5 0
4 years ago
Rewrite ^5 square root of 4 * square root of 2 as a single radical
Irina-Kira [14]
The answer is the first one in the options
3 0
3 years ago
Read 2 more answers
Verify that the divergence theorem is true for the vector field f on the region
schepotkina [342]
\mathbf f(x,y,z)=5x\,\mathbf i+xy\,\mathbf j+2xz\,\mathbf k

\mathrm{div}(\mathbf f)=\dfrac{\partial(5x)}{\partial x}+\dfrac{\partial(xy)}{\partial y}+\dfrac{\partial(2xz)}{\partial z}=5+x+2x=5+3x


By the divergence theorem, the flux of \mathbf f across the boundary of E is given by


\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_E\mathrm{div}(\mathbf f)\,\mathrm dV

=\displaystyle\int_{z=0}^{z=2}\int_{y=0}^{y=2}\int_{x=0}^{x=2}(5+3x)\,\mathrm dx\,\mathrm dy\,\mathrm dz=64
4 0
4 years ago
Use two rectangles of equal width to estimate the area between the graph of f(x) = x + cos(πx) and the x-axis on the interval [2
MrRissso [65]
We find the base of the rectangles by taking the difference between the interval endpoints, and dividing by 2.
Base of rectangle = (6 - 2) / 2
= 2

The area of the first rectangle:

(4 - 2)f(4) = 2[4 + cos(4π)]


The area the second triangle:

(6 - 4)f(6) = 2[6 + cos(6π)]


Now just compute the two areas and combined them. That will give you the estimated under the curve.


To evaluate the midpoint of each rectangle, we take the midpoint of the base lengths of each rectangle. This midpoint is the x value. Then evaluate the function at that x value.


The midpoint of the first rectangle is x=3. Evaluate f(3).
The midpoint of the second rectangle is x=5. Evaluate f(5).
7 0
3 years ago
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