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kodGreya [7K]
3 years ago
14

-4 - (-13) = What is the difference?

Mathematics
2 answers:
eduard3 years ago
7 0

Answer:

9

Step-by-step explanation:

Alex3 years ago
4 0

Answer:

−4−(−13)

=−4−(−13)

=−4+13

=9

Step-by-step explanation:

Please mark brainllest!

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Can u guys plz give me the answer to number 1-3
jek_recluse [69]
I'm pretty sure it is 5:55


8 0
3 years ago
Which choices are equivalent to the quotient below √16/√8
Darya [45]

Answer:

A

Step-by-step explanation:

\frac{\sqrt{16} }{\sqrt{8} }  = \sqrt{\frac{16}{8} }  = \sqrt{2}

Hope this helps!

8 0
3 years ago
Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x​
Tanzania [10]

Recall that

\cosh^2(x) - \sinh^2(x) = 1

Dividing both sides by cosh²(x) gives

1 - \tanh^2(x) = \mathrm{sech}^2(x)

Also, recall the identity

\sinh(2x) = 2\sinh(x)\cosh(x)

Then

\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)

4 0
3 years ago
Solve for x using basic trigonometric ratios.
yuradex [85]
Sine 35 degrees = x / 20

x = sine 35 degrees * 20

x = .57358 * 20

x = 11.4716


8 0
3 years ago
Round to the nearest hundredth: 2.0625
AURORKA [14]

Answer:

2.06

Step-by-step explanation:

lmk if u need an explanation

5 0
3 years ago
Read 2 more answers
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