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3 years ago

Lindsay pays $75.00 each month and her employer pays a total of $3,000.00 per year; find the annual health insurance premium.

Mathematics

1 answer:

xxMikexx [17]3 years ago

3 0

Divide or multiply til it fits one of those

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500+2000+45+338+2145

Semenov [28]

Answer:

5,028

Step-by-step explanation:

7 0

3 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

4 years ago

Determine whether the statement is true or false. If it is true, explain why.

Over [174]

True.

Since $y^4 \geq 0$ , $y' = -1 - y^4 \ \textless \ 0$ and the solutions are decreasing functions.

8 0

3 years ago

WILL MAKE BRAINLIST!!!!!!

bixtya [17]

Answer:

To do this, subtract 6 from both sides. − 3_x_ + 6 − 6 > 12 − 6. −3_x_ > 6. Now divide both sides of the inequality by −3. Since you're dividing by a negative number, you need to flip the inequality sign.

Step-by-step explanation:

4 0

3 years ago

Which weights more 2.48 or 2.5

Mazyrski [523]

2.5 weighs more. It’s a greater number than 2.48

6 0

3 years ago