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stepan [7]
3 years ago
13

Find the answer! 10 points to the first person!

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0

Answer:

36

Step-by-step explanation:

This is a 30, 60 90 triangle, which means that there is a ration for calculating each side.

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Given the following equation, at what point will the graph intersect? f(x) =5x+1 g(x)= -2x+15
Andru [333]

Answer: (2,11)

Step-by-step explanation:

To find the point where the functions will intersect, we want to find the place that they are equal to each other. We do this by setting the equations equal to each other.

5x+1=-2x+15                       [add both sides by 2x]

7x+1=15                               [subtract both sides by 1]

7x=14                                  [divide both sides by 7]

x=2

Now, we know that the functions intersect at x=2. To find the point, we would plug x back into both equations to ensure that the points are the same.

f(2)=5(2)+1                         [multiply]

f(2)=10+1                            [add]

f(2)=11

The point on f(x) is (2,11).

g(2)=-2(2)+15                    [multiply]

g(2)=-4+15                         [add]

g(2)=11

The point on g(x) is (2,11).

Since the point at x=2 is the same for f(x) and g(x), we know that the graph intersects at (2,11).

8 0
3 years ago
Hamburger buns come in packages of 8. Pre-made hamburger patties come in boxes of 10. Billy would like to buy the smallest numbe
ankoles [38]

Answer:

well you need to do something

Step-by-step explanation:

8 0
2 years ago
A jogger runs 8 miles north and then 5 miles west. What is the shortest distance, to the nearest tenth of a mile, he must travel
Stells [14]

Answer:

most likely has to run 13 miles southeast or 5 miles east and  8 west  

Step-by-step explanation:

5 0
3 years ago
Can anyone help me with this?
arsen [322]

Answer :The answer is B.

4 0
3 years ago
Read 2 more answers
PLS HELPP! ITS TIMED
Maru [420]

Answer:

Neg will be on 2nd one

Pos will be on 3rd one

Unde will be on 4th one

Zero will be one 1st one

7 0
2 years ago
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