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3 years ago

Find the approximate height of the cylinder. Use 3.14 for π.

Mathematics

1 answer:

babymother [125]3 years ago

6 0

Answer: The height is 5.2 cm.

Step-by-step explanation:

146.952 = n r^2 h

146.952= 3.14 * 9 *h

146.952= 28.26 h divide both sides by 28.26

h = 5.2

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allochka39001 [22]

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3 years ago

A rope is 225 centimeters long.

n200080 [17]

Answer:

This is impossible, unless you meant centimeters. If you did, then the answer would be 113.

Step-by-step explanation:

225 - 112 = 113.

8 0

3 years ago

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.

goldfiish [28.3K]

<span>To write a two-variable equation, you would first need to know how much Mayaâ€™s allowance was. Then, you would need the cost of playing the arcade game and of riding the Ferris wheel. You could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. Your variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation you could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.</span>

4 0

3 years ago

How can I solve 900-382?

BlackZzzverrR [31]

899

900

- 382

<h3> 517</h3><h3>Hope this helps</h3>

6 0

2 years ago

A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects

Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let <em>X</em> denote the number of green candies.

The probability of green candies is, <em>p</em> = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, <em>n</em> = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

$P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328$

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

= 0.17228 + 0.17946 + 0.15328

= 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

7 0

3 years ago