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Taya2010 [7]
3 years ago
11

2. Why was Susan Weiss' work not considered important?

Mathematics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

she was a woman.

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Consider the curve of the form y(t) = ksin(bt2) . (a) Given that the first critical point of y(t) for positive t occurs at t = 1
mafiozo [28]

Answer:

(a).   y'(1)=0  and    y'(2) = 3

(b).  $y'(t)=kb2t\cos(bt^2)$

(c).  $ b = \frac{\pi}{2} \text{ and}\  k = \frac{3}{2\pi}$

Step-by-step explanation:

(a). Let the curve is,

$y(t)=k \sin (bt^2)$

So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value x_{0}  which lies in the domain of f where the derivative is 0.

Therefore,  y'(1)=0

Also given that the derivative of the function y(t) is 3 at t = 2.

Therefore, y'(2) = 3.

(b).

Given function,    $y(t)=k \sin (bt^2)$

Differentiating the above equation with respect to x, we get

y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)]

Applying chain rule,

y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)  

(c).

Finding the exact values of k and b.

As per the above parts in (a) and (b), the initial conditions are

y'(1) = 0 and y'(2) = 3

And the equations were

$y(t)=k \sin (bt^2)$

$y'(t)=kb2t\cos (bt^2)$

Now putting the initial conditions in the equation y'(1)=0

$kb2(1)\cos(b(1)^2)=0$

2kbcos(b) = 0

cos b = 0   (Since, k and b cannot be zero)

$b=\frac{\pi}{2}$

And

y'(2) = 3

$\therefore kb2(2)\cos [b(2)^2]=3$

$4kb\cos (4b)=3$

$4k(\frac{\pi}{2})\cos(\frac{4 \pi}{2})=3$

$2k\pi\cos 2 \pi=3$

2k\pi(1) = 3$  

$k=\frac{3}{2\pi}$

$\therefore b = \frac{\pi}{2} \text{ and}\  k = \frac{3}{2\pi}$

7 0
4 years ago
Please help me 19 points ! I inserted a image of the problem
bija089 [108]

Answer:

first tile: x=5, second tile x=19, third tile x=29, last tile x=6

Step-by-step explanation:

Ohhh is that edmentum i do that too! ;)

(x-1)^3=64

x-1=4

x=5

(x-3)^5=2^20

x-3=2^4

x-3=16

x=19

(x-4)^3=5^6

x-4=25

x=29

the last one has to be x=6

3 0
4 years ago
If tan2<br> x = 3 then value of<br> x is
MAVERICK [17]

Answer:

If tan2 x = 3 then the value of x is 3. So three is your answer!

Step-by-step explanation:

8 0
3 years ago
M(n+r)=s solve for n. Show two methods.
Serga [27]

9514 1404 393

Answer:

  1. n = (s/m) -r
  2. n = (s -mr)/m

Step-by-step explanation:

1. Undo the operations done to n, in reverse order. Here, n has r added and the sum is multiplied by m. First we divide by m, then we subtract r.

  m(n+r) = s . . . given

  n +r = s/m . . . divide by m

  n = (s/m) -r . . . subtract r

__

2. Eliminate the parentheses, then proceed as above. Subtract the added term, then divide by the coefficient of n.

  m(n+r) = s

  mn +mr = s . . . eliminate parentheses

  mn = s -mr . . . subtract the added term

  n = (s -mr)/m . . . divide by the coefficient of n

4 0
3 years ago
Solve for 18% of 30. DO NOT ROUND
elena-s [515]

Answer:5.4

Step-by-step explanation:

30% of 18= 18% of 30

10% of 18= 1.8

1.8 times 3=5.4

8 0
3 years ago
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