You were the 35th caller, 5 and 7 have a product of 35
The complete fractional question given in the above picture is 55/3 = 1 + 52/3 = 2 + 49/3 = 5 + 40/3 = 8 + 31/3 = 10 + 25/3
<h3>Fraction</h3>
Let
55/3 = 1 + x/3
55/3 = (3+x) / 3
55/3 × 3 = 3 + x
55 = 3 + x
55 - 3 = x
52 = x
55/3 = 2 + x/3
55/3 =(6+x) / 3
55/3 × 3 = 6+x
55 = 6 + x
55 - 6 = x
49 = x
55/3 = x + 40/3
55/3 = (3x+40) / 3
55/3 × 3 = 3x + 40
55 = 3x + 40
55 - 40 = 3x
15 = 3x
x = 15/3
x = 5
55/3 = x + 31/3
55/3 = (3x+31) / 3
55/3 × 3 = 3x + 31
55 = 3x + 31
55 - 31 = 3x
24 = 3x
x = 24/3
x = 8
55/3 = 10 + x/3
55/3 = (30+x) / 3
55/3 × 3 = 30 + x
55 = 30 + x
55 - 30 = x
25 = x
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A. 3279 because the first 7 terms are 3,9,27,81,243,729,2187
Answer:
There are 36 peanuts in the bag.
Step-by-step explanation:
4 over 3;48 over x. 4x12=48 so 3x12=36
I. -7/10
K. 675/1000 or 27/40
M. -26/100
O. 5 55/100 the 5 by itself is a whole number
J 84/100 or 21/25
L -252/1000
N 2 78/100
p 11 688/100
