Question

1) The perimeter of a rectangular classroom floor is 90 feet. The length of the floor is twice the

Answer 1

Answer: The equation would NOT help us solve for the length and width of the classroom is "$x + 2y = 90$".

Step-by-step explanation:

Let y be the width of the rectangular classroom floor and x be the length of the rectangular classroom floor .

Given ,

The perimeter of a rectangular classroom floor is 90 feet.

The length of the floor is twice the  width.

i.e. Length =2 (width)

i.e. x= 2y ..(i)

Also, perimeter = 2(length+width)

$i.e. 2(x+y)=90\\\\\Rightarrow\ 2x+2y=90$

When we put value of x from (i), we get

$2(2y) + 2y = 90$

Hence, the equation would NOT help us solve for the length and width of the classroom is "$x + 2y = 90$".