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Romashka-Z-Leto [24]
3 years ago
15

Which shows how the distributive property can be used to evaluate 7x8 4/5?

Mathematics
2 answers:
masha68 [24]3 years ago
7 0

Answer: 56 + 28/5

Step-by-step explanation:

Yuri [45]3 years ago
5 0

Answer:

61 3/5

Step-by-step explanation:

we realize that 8 4/5 can be written as [8 + (4/5)]

hence 7 x 8 4/5

= 7 x [8 + (4/5)]

= 7 [8 + (4/5)]   (use the distributive property, see attached for reference)

= 7(8) + 7(4/5)

= 56 + 28/5  (convert 28/5 into mixed fraction)

= 56 + 5 3/5

= 61 3/5 (answer)

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4 years ago
What is the value of (7 +21)(3 - i)?
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8 0
3 years ago
(sqrt3-sqrt3i)^4
Ludmilka [50]

The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

<h3>Absolute values of the complex numbers</h3>

The absolute values of the complex numbers are determined as follows;

(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

|z| = \sqrt{(\sqrt{3} )^2 + (\sqrt{3 }\times1 )^2} } \\\\|z| = \sqrt{6}

(-1+sqrt3i)^12 = (-1 + √3i)¹²

|z| = \sqrt{(-1)^2 + (\sqrt{3)^2} } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt 3-i)^6 = (√3 - i)⁶

|z| = \sqrt{(\sqrt{3})^2 + (-1)^2 } \\\\|z| = \sqrt{4} \\\\|z| = 2

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

|z| = \sqrt{(\sqrt{2} )^2 + (\sqrt{2})^2 } \\\\|z| = 2

(sqrt2-i)^6 = (√2 - i)⁶

|z| = \sqrt{(\sqrt{2})^2 + (-1)^2} } \\\\|z| = \sqrt{3}

Increasing order of the complex numbers;

(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ =  (-1 + √3i)¹² < (√3 - √3i)⁴.

Learn more about complex numbers here: brainly.com/question/10662770

#SPJ1

3 0
3 years ago
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