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Pie
3 years ago
13

Classify the system of equations.

Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0
These two lines are parallel
You can use desmos

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A customer purchased a total of 16 washcloths and towels. Each washcloth cost $10.50 and each towel cost $15.00. The customer sp
IgorC [24]

Answer:

3

Step-by-step explanation:

10.50 x 3 = 31.5

15 x 13 = 195

195 + 31.5 = 226.50

8 0
2 years ago
Ind the next term for the given sequence.52, 45, 38, 31,
o-na [289]
The answer is 24. To get from one term to the next, you have to find the difference. To get from 52 to 45, you minus 7. It is the same with the other terms. So 31 - 7 = 24
4 0
3 years ago
Read 2 more answers
Simplify: −√16x^2 , when x<0
Savatey [412]

Answer:

-4|x|

Step-by-step explanation:

To simplify :

-\sqrt{16x^2} , when x

In order to simplify the given expression we will take the square root of the term inside the root.

The term in the square root are perfect squares (square of an integer), so, we can write them in square of the numbers.

⇒ -\sqrt{(\pm4x)^2}   [As (\pm4x)^2=16x^2]

On taking square root the square gets removed. So, we have,

⇒ -(\pm4x)

⇒ -4|x|

Since x, so the value would be negative.

So, simplified answer is

-4|x|  (Answer)

3 0
3 years ago
What is the average rate of change for this function for the interval from x=3 to x=5?
SSSSS [86.1K]

Answer:

A. 49

Step-by-step explanation:

The average rate of change for the interval ranging from x = 3 to x = 5 for the given function represented in the table above can be calculated using:

Average rate of change = \frac{f(x2) - f(x1)}{x2 - x1}

x2 = 5

x1 = 3

f(x2) = f(5) = 125

f(x1) = f(3) = 27

Thus,

Average rate of change = \frac{125 - 27}{5 - 3}

= \frac{98}{2}

Average rate of change = 49

Average rate of change of the given table values representing an exponential function is A. 49.

4 0
3 years ago
An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d
denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. w\times 2w\times h=36

h=\frac{18}{w^2}

The equation form when top is open,

f(w)=2w^2+2wh+2(2w)h

Substitute the value of h,

f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})

f(w)=2w^2+\frac{36}{w}+\frac{72}{w}

f(w)=2w^2+\frac{108}{w}

Derivate w.r.t 'w',

f'(w)=4w-\frac{108}{w^2}

For critical point put it to zero,

4w-\frac{108}{w^2}=0

4w=\frac{108}{w^2}

w^3=27

w^3=3^3

w=3

Derivate the function again w.r.t 'w',

f''(w)=4+\frac{216}{w^3}

For w=3, f''(3)=4+\frac{216}{3^3}=12 >0

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = \frac{18}{3^2}=2\ ft

Therefore, the dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

4 0
3 years ago
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