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Pie
3 years ago
13

Classify the system of equations.

Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0
These two lines are parallel
You can use desmos

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A triangle has 2 sides that equal 6 inches. The other side equals 4 inches. What kind of triangle is this
Tom [10]
Ισοσκελες τρίγωνο
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7 0
3 years ago
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Answer this question!!!!!!!​
Vesnalui [34]

The expression can represent the value of x in terms of R, m, n and k after rearranging.

<h3>What is an expression?</h3>

It is defined as the combination of constants and variables with mathematical operators.

It is given that:

The expression is:

\rm R = 4m\sqrt{\dfrac{xn}{k^3}}

Square both side:

\rm R^2 = 16m^2{\dfrac{xn}{k^3}}

16m² x n = R²k³

x = (R²k³)/(16m²n)

The above expression represents the value of x in terms of R, m, n and k.

Thus, the expression can represent the value of x in terms of R, m, n and k after rearranging.

Learn more about the expression here:

brainly.com/question/14083225

#SPJ1

8 0
2 years ago
Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
Please help 10 points
WARRIOR [948]

Answer:

FG = 15

Step-by-step explanation:

Note that

EF + FG = EG ← substitute values into equation, that is

6 + FG = 21 ( subtract 6 from both sides )

FG = 21 - 6 = 15

5 0
3 years ago
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Can someone please give me the answer
bulgar [2K]

Answer:

12  and square

Step-by-step explanation:

5 0
3 years ago
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