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3 years ago

PLZ HELP ME W THIS !!! MARKIN BRAINIEST !!!

Mathematics

1 answer:

satela [25.4K]3 years ago

5 0

Answer:

Step-by-step explanation:

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Draw 8 lines that are between 1 inch and 3 inches long. Measure each line to the nearest fourth inch, and make a line plot.

IRISSAK [1]

The length of the line is the difference between the endpoints of the line

The length of each line to the nearest fourth inch is 0.25 inch

<h3>How to measure the length of each line</h3>

The length of the horizontal line is given as:

Length = 2 inches

This is calculated as:

Length = 3 inches - 1 inch

Length = 2 inches

8 lines are to be drawn between the 1 inch and 3 inches point.

So, the length (l) of each line is:

$l = \frac{2\ inches}{8}$

Simplify the fraction

$l = \frac{1\ inches}{4}$

Divide

$l = 0.25\ inch$

Hence, the length of each line to the nearest fourth inch is 0.25 inch

Read more about line measurements at:

brainly.com/question/14366932

6 0

1 year ago

2x(9-5x) - (-4x-36x)

allochka39001 [22]

I got 48x
First by distributing 2x to 9-5x=
18x-10x
Then adding a 1 in front of - making -4x-36x to 4x+36x=40x
8x+40x=48x

7 0

3 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

3 years ago

Best answer gets brainliest!

nikitadnepr [17]

Answer: <u>Best answer gets brainliest!</u>

Step-by-step explanation:

<u>Add the amount of students together!</u>

Hopefully this helps you!

-Keira

4 0

2 years ago

Read 2 more answers

Show how to use the distributive property to simplify 4(5+x).

VladimirAG [237]

Answer:

Step-by-step explanation:

Ur mom

8 0

3 years ago