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Aleks04 [339]
3 years ago
13

Give Brainiest

Mathematics
2 answers:
inn [45]3 years ago
5 0

Answer:y= -30x+150

Step-by-step explanation:So 150/5=30 which are the number of weeks and the total number of songs.

Since every week she downloads 5 songs this makes the total quantity which makes it go less makes the 30 a negative number.

Initial number is 150 since its the total of songs that are in total.

M=(120-150)/(1-0)=-30

Line equation

y=150=-30(x-0)

y=-30x+150

swat323 years ago
4 0

Answer:

A) rate of change would be dividing the number of songs wanted (150) by the number of weeks downloading (5)

150/5 = 30

 since the total quantity wanted is becoming less every week the rate of change would be negative so it becomes -30

Initial value is 150, which is the total number of songs they want

             B) rate of change would be dividing the number of songs wanted (150) by the number of weeks downloading (5)

150/5 = 30

 since the total quantity wanted is becoming less every week the rate of change would be negative so it becomes -30

Initial value is 150, which is the total number of songs they want

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Find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.5414. (b)
Akimi4 [234]

Answer:

Part (a) The value of Z is 0.10396. Part (b) The value of Z is 0.410008.

Step-by-step explanation:

Consider the provided information.

Part (a)

In order to find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.5414, simply find 0.5414 in the table and search for the appropriate Z-value.

Now, observing the table it can be concluded that the value of Z is 0.10396.

Part (b)

Consider the number 65.91%

The above number can be written as 0.6591.

Now, find 0.6591 in the table and search for the appropriate Z-value.

By, observing the table it can be concluded that the value of Z is 0.410008.

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GenaCL600 [577]
Hoi!

To solve this, first plug in the values for x and y.

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8 +1 \frac{1}{2} = 9 \frac{1}{2}

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