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3 years ago

Using graphing paper,determine the line described by the given point and slope

Mathematics

1 answer:

vichka [17]3 years ago

7 0

Answer:

Step-by-step explanation:

What is slope of ( 0 , 6) and ( 6 , 7)?. Algebra · Geometry · Trigonometry · Calculus · Worksheets · Math Gifs; Teacher Tools. Test Grade Calculator ...

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Please I need help!!!!!!

8090 [49]

Answer:

What? I'm in middle school ;-;

Step-by-step explanation:

8 0

3 years ago

What is the solution of the equation (x – 5)^2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.

xz_007 [3.2K]

Answer:

$x = \dfrac{7 \pm 3i\sqrt{3}}{2}$

Step-by-step explanation:

(x – 5)^2 + 3(x – 5) + 9 = 0

This is a quadratic equation in x - 5.

Let u = x - 5, then the quadratic equation becomes:

u^2 + 3u + 9 = 0

We can use the quadratic formula to solve for u.

$u = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$u = \dfrac{-3 \pm \sqrt{3^2 - 4(1)(9)}}{2(1)}$

$u = \dfrac{-3 \pm \sqrt{9 - 36}}{2}$

$u = \dfrac{-3 \pm \sqrt{-27}}{2}$

$u = \dfrac{-3 \pm 3i\sqrt{3}}{2}$

Since u = x - 5, now we substitute x - 5 for u and solve for x.

$x - 5 = \dfrac{-3 \pm 3i\sqrt{3}}{2}$

$x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + 5$

$x = \dfrac{-3 \pm 3i\sqrt{3}}{2} + \dfrac{10}{2}$

$x = \dfrac{7 \pm 3i\sqrt{3}}{2}$

7 0

3 years ago

Solve this asap plsss Giving 20 points ty <3

SCORPION-xisa [38]

Answer:

Step-by-step explanation:

first 2×2=4

then 16÷4

4×6

5 0

3 years ago

15) The graph models the cost of a cheese pizza with extra toppings at two different restaurants. According to the graph, about

Vladimir [108]

Answer:

have no idea

Step-by-step explanation:

5 0

3 years ago

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0

3 years ago