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FinnZ [79.3K]
3 years ago
13

What is the area? 7 m 4 m square meters?

Mathematics
1 answer:
bija089 [108]3 years ago
3 0

Answer:

28 square meters

Step-by-step explanation:

7 x 4= 28

28 square meters

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An automobile manufacturer wants to assess a new style of visual display to see if it changes the amount of reported eye-strain
finlep [7]

Answer:

Standard error = 0.34

t-statistic = 11.18

Step-by-step explanation:

Given Data:

Mean difference d = 3.8

Standard deviation S.D = 1.36

Number of people = 16

The appropriate test are:

1. Standard error

2. T- statistic

1. Calculating the standard error using the formula;

Standard error = S.D/√n

                         = 1.36/√16

                          = 1.36/4

                           = 0.34

2. Calculating the t-statistic using the formula;

t-statistic = d/(S.D/√n)

              = 3.8/(1.36/√16)

              = 3.8/(1.36/4)

              = 3.8/0.34

               = 11.18

7 0
4 years ago
2.(03.01 LC)
ale4655 [162]
592,722 is the correct answer
3 0
3 years ago
Read 2 more answers
Calculus 3 help please.​
Reptile [31]

I assume each path C is oriented positively/counterclockwise.

(a) Parameterize C by

\begin{cases} x(t) = 4\cos(t) \\ y(t) = 4\sin(t)\end{cases} \implies \begin{cases} x'(t) = -4\sin(t) \\ y'(t) = 4\cos(t) \end{cases}

with -\frac\pi2\le t\le\frac\pi2. Then the line element is

ds = \sqrt{x'(t)^2 + y'(t)^2} \, dt = \sqrt{16(\sin^2(t)+\cos^2(t))} \, dt = 4\,dt

and the integral reduces to

\displaystyle \int_C xy^4 \, ds = \int_{-\pi/2}^{\pi/2} (4\cos(t)) (4\sin(t))^4 (4\,dt) = 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt

The integrand is symmetric about t=0, so

\displaystyle 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \,dt

Substitute u=\sin(t) and du=\cos(t)\,dt. Then we get

\displaystyle 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^1 u^4 \, du = \frac{2^{13}}5 (1^5 - 0^5) = \boxed{\frac{8192}5}

(b) Parameterize C by

\begin{cases} x(t) = 2(1-t) + 5t = 3t - 2 \\ y(t) = 0(1-t) + 4t = 4t \end{cases} \implies \begin{cases} x'(t) = 3 \\ y'(t) = 4 \end{cases}

with 0\le t\le1. Then

ds = \sqrt{3^2+4^2} \, dt = 5\,dt

and

\displaystyle \int_C x e^y \, ds = \int_0^1 (3t-2) e^{4t} (5\,dt) = 5 \int_0^1 (3t - 2) e^{4t} \, dt

Integrate by parts with

u = 3t-2 \implies du = 3\,dt \\\\ dv = e^{4t} \, dt \implies v = \frac14 e^{4t}

\displaystyle \int u\,dv = uv - \int v\,du

\implies \displaystyle 5 \int_0^1 (3t-2) e^{4t} \,dt = \frac54 (3t-2) e^{4t} \bigg|_{t=0}^{t=1} - \frac{15}4 \int_0^1 e^{4t} \,dt \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} e^{4t} \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} (e^4 - 1) = \boxed{\frac{5e^4 + 55}{16}}

(c) Parameterize C by

\begin{cases} x(t) = 3(1-t)+t = -2t+3 \\ y(t) = (1-t)+2t = t+1 \\ z(t) = 2(1-t)+5t = 3t+2 \end{cases} \implies \begin{cases} x'(t) = -2 \\ y'(t) = 1 \\ z'(t) = 3 \end{cases}

with 0\le t\le1. Then

ds = \sqrt{(-2)^2 + 1^2 + 3^2} \, dt = \sqrt{14} \, dt

and

\displaystyle \int_C y^2 z \, ds = \int_0^1 (t+1)^2 (3t+2) \left(\sqrt{14}\,ds\right) \\\\ ~~~~~~~~ = \sqrt{14} \int_0^1 \left(3t^3 + 8t^2 + 7t + 2\right) \, dt \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 t^4 + \frac83 t^3 + \frac72 t^2 + 2t\right) \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 + \frac83 + \frac72 + 2\right) = \boxed{\frac{107\sqrt{14}}{12}}

8 0
1 year ago
Joshua's family took a road trip to Mount Rushmore. Joshua fell asleep 35% of the way through the trip. If the total length of t
stiks02 [169]
You need to calculate 35% of 400.

The way I do this on paper is I split it up into chunks and then add the chunks together.

First I would calculate 10%. To do this, divide 400 by 10, because to get from 100% to 10% you must divide by 10.

So 10% = 40

You need 30%, so you just multiply by 3, because to get from 10% to 30%, you multiply by 3.

So 30% = 120

5% is half of 10% so half of 40 is 20.

So 5% = 20

30% + 5% = 35%

120 + 20 = 140

So they had traveled 140 miles when Joshua fell asleep. Hope this helps :)
4 0
3 years ago
Read 2 more answers
What is 1/5 of 1/2 of 1/4 of 152?
Alona [7]
1/5 of 152 is 30.4
1/2 of 152 is 76
1/4 of 152 is 38

hope this helped :)



4 0
4 years ago
Read 2 more answers
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