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Goryan [66]
3 years ago
8

Determine weather it is no solution many solutions or one solutions 3(6-4m)=2(9-6m)

Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

Many solutions

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%7D%7B4%7D%20%20%2B%202%20%3D%204x%20-%201" id="TexFormula1" title=" \frac{3x}{
ASHA 777 [7]

Answer:

x=\frac{12}{13}

Step-by-step explanation:

\frac{3x}{4} +2=4x-1\\\\4x - \frac{3x}{4} = 2+1\\\\\frac{13x}{4} =3\\\\13x=12\\\\x=12/13

7 0
3 years ago
4x-4/5x+10•30x+60/2x-2
slamgirl [31]
Order of Operations. PEMDAS, Parentheses, Exponents, Multiply, Divide, Add, Subtract. Multiply; 4x-4/5x+300x+60/2x-2. Divide; 4x-0.8x+300x+30x-2. Add; 4x-330.8x-2. Subtract; 326.8x-2. 
Your answer; 326.8x-2
5 0
3 years ago
Plz help
AfilCa [17]

Answer:

Step-by-step explanation:

Given : Casey was at the surface of a swimming pool and recorded the following two measurements, in feet, on a number line: −8, which represents the depth of water in the swimming pool +7, which represents the height of the slide at the pool  

To Find : What does 0 represent in this situation?  

Describe the height of the slide in relation to 0 in the situation

Casey held a pole in the swimming pool. The bottom of the pole was at a depth of 2 feet. How should Casey mark the level of the bottom of the pole on the number line

Solution

0 represent in this situation  - Top surface of Swimming pool  - Surface matching with ground

height of the slide in relation to 0 in the situation  = 7 feet

pole was at a depth of 2 feet  = - 2

4 0
3 years ago
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
john has $1,000 in his bank account. each month he deposits $150 y=150x + 1000 determine what is the independent and dependent v
Vlad1618 [11]
1,000 is independent because nothing it changing it.

150x is dependent because 150 relies on the variable x.
8 0
3 years ago
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