I think it is 15 but I want to see what you guys get and break it down please because sometimes people will say what they got an
d y'all be saying "yeah it's correct yeah" when it's really not. 
2 answers:
You might be interested in
Answer:
The probability is 0.02667
Step-by-step explanation:
Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.
So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = P(D2∩D1)/P(D1)
Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:
At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:
P(A)=1/3
P(B)=1/3
P(C)=1/3
Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)
P(D2/D1) = 0.02667